MATRICES INVERSA SOLUCION EJERCICIO 3.docx
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8/17/2019 MATRICES INVERSA SOLUCION EJERCICIO 3.docx
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EJERCICIOS RESUELTOS. CÁLCULO DE MATRICESINVERSAS:
1. DETERMINA LAS MATRICES INVERSAS DE SER POSIBLE, DE LAS SIGUIENTESMATRICES:
a)
−211
720
654
SOLUCIONES:
1. CÁLCULO DE MATRICES INVERSAS:FÓRMULA PARA EL CÁLCULO DE MATRICES INVERSAS POR EL MÉTODO DELOS COFACTORES:
( ) A
Aadj A
t
det
1 =−
Dond( )t Aadj
!"#n"$%a &a'(" ad*+n'a d a '(an!-+!'a d a &a'(" A. Laad*+n'a ! d'(&"na &d"an' %%+o d %ada +no d !+! &n'o!a'nd"ndo &-ando a /0(&+a:
( ) ij ji
ij M A ⋅−= +1
, dondij M
! d'(&"nan' &no( + (!+'a d "&"na( a
$a " 2 a %o+&na * d a &a'(" '(an!-+!'a.D'(&"n&o! -("&(o d'(&"nan' d a &a'(", -+! a %ond"%"0nn%!a("a -a(a + +na &a'(" 'n#a "n3(!a ! + !+ d'(&"nan' !a%(o:
= A
−
211
720
654
D'(&"n&o! -("&(o d'(&"nan' d a &a'(":
( ) ( ) ( ) ( ) ( ) ( )052417126751610224
720
654
211
720
654
××−××−×−×−××+××+×−×=
−
−
30281235016 =−−+++−=
D'(&"n&o! a &a'(" '(an!-+!'a d A:
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−=
276
125
104
t A
• E&n'o11
A
! o4'"n "&"nando a $a 1 2 a %o+&na 1:
−=276
125
104
t A
E d'(&"nan' &no(
117427
12
11 −=−−=
−= M
A-"%ando a /0(&+a:( ) ( ) 111111 2
11
11
11 −=−×−=⋅−= + M A
•
E&n'o
12 A
! o4'"n "&"nando a $a 1 2 a %o+&na 5:
−=
276
125
104
t A
E d'(&"nan' &no(
461026
15
12 =−== M
A-"%ando a /0(&+a:( ) ( ) ( ) 4411 3
12
21
12 −=−=⋅−= + M A
• E&n'o
13 A
! o4'"n "&"nando a $a 1 2 a %o+&na 6:
−=
276
125
104
t A
E d'(&"nan' &no(
47123576
25
13 =+=
−= M
A-"%ando a /0(&+a:( ) ( ) ( ) 474711 4
12
31
13 =−=⋅−= + M A
• E&n'o21
A
! o4'"n "&"nando a $a 5 2 a %o+&na 1:
−=
276
125
104
t A
E d'(&"nan' &no(
77027
10
21 −=−== M
A-"%ando a /0(&+a:
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( ) ( ) ( ) 7711 321
12
21 =−−=⋅−= + M A
• E&n'o22
A
! o4'"n "&"nando a $a 5 2 a %o+&na 5:
−=
276
125
104
t A
E d'(&"nan' &no(
26826
14
22 =−== M
A-"%ando a /0(&+a:( ) ( ) ( ) 2211 4
22
22
22 =−=⋅−= + M A
• E&n'o23
B
! o4'"n "&"nando a $a 5 2 a %o+&na 6:
−=
276
125
104
t A
E d'(&"nan' &no(
2802876
04
23 =+== M
A-"%ando a /0(&+a:( ) ( ) ( ) 282811 5
23
32
23 −=−=⋅−= + M A
• E&n'o31
A
! o4'"n "&"nando a $a 6 2 a %o+&na 1:
−=
276
125
104
t A
E d'(&"nan' &no(
22012
10
31 =+=
−= M
A-"%ando a /0(&+a:( ) ( ) ( ) 2211 4
31
13
31 =−=⋅−= + M A
• E&n'o32
A
! o4'"n "&"nando a $a 6 2 a %o+&na 5:
−=
276
125
104
t A
E d'(&"nan' &no(
15415
14
32 −=−== M
A-"%ando a /0(&+a:( ) ( ) ( ) 1111 5
32
23
32 −=−−=⋅−= + M A
• E&n'o33
A
! o4'"n "&"nando a $a 6 2 a %o+&na 6:
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−=
276
125
104
t A
E d'(&"nan' &no(
80825
04
33 −=+−=
−= M
A-"%ando a /0(&+a:
( ) ( ) ( ) 8811 633
33
33 −=−−=⋅−= + M A
Tn"ndo 'odo! o! &n'o! d a &a'(" ad*+n'a d a '(an!-+!'a, ao(dna&o!:
( )
−−
−−=
812
2827
47411
t Aadj
A-"%ando a /0(&+a -a(a %%+o d a &a'(" "n3(!a:( ) A
Aadj A
t
det
1 =−
−
−
−−
=
−−
−−=−
3
8
3
1
3
2
3
28
3
2
3
7
3
47
3
4
3
11
812
2827
47411
3
11 A