PRCTICA DOMICILIARIA

PROBLEMA 1.- Determinar las cotas de los vrtices de la siguiente red de nivelacin.a. Sin considerar las distancias.b. Teniendo en cuenta las distancias.

SOLUCIN a:

Determinacin del nmero de Ecuaciones Condicionales (C).

C = #n - #S + #QC = 16 11 + 1C = 6 ec. Condicionales independientes.

Ecuaciones Condicionales:

CIRCUITO I:

V1 + V2 V12 + 0.006 = 0 -- f1 = 0

CIRCUITO II:

V3 V11 + V12 V13 0.022 = 0 -- f2 = 0

CIRCUITO III:

-V9 V10 + V13 + V14 0.018 = 0 -- f3 = 0

CIRCUITO IV:

V4 V8 V14 + V15 0.042 = 0 -- f4 = 0

CIRCUITO V:

V5 V15 V16 0.032 = 0 -- f5 = 0

CIRCUITO VI:

-V6 V7 + V16 + 0.005 = 0 -- f6 = 0CUANDRO RESUMEN DE LAS ECUACIONES CONDICIONALES

V1V2V3V4V5V6V7V8V9V10V11V12V13V14V15V16K

1a1 = 1a2 = 1a3 = 0a4 = 0a5 = 0a6 = 0a7 = 0a8 = 0a9 = 0a10 = 0a11 = 0a12 = -1a13 = 0a14 = 0a15= 0a16 = 00.006

2b1=0b2 = 0b3 = 1b4 = 0b5 = 0b6 = 0b7 = 0b8 = 0b9 = 0b10 = 0b11 = -1b12 = 1b13 = -1b14 = 0b15 = 0b16 = 0-0.022

3c1 = 0c2 = 0c3 = 0c4 = 0c5 = 0c6 = 0c7 = 0c8 = 0c9 = -1c10 = -1c11 = 0c12 = 0c13 = 1c14 = 1c15 = 0c16 = 0-0.018

4d1 = 0d2 = 0d3 = 0d4 = 1d5 = 0d6 = 0d7 = 0d8= -1 d9 = 0d10 = 0d11 = 0d12 = 0d13 = 0d14 = -1d15 = 1d16 = 0-0.042

5e1 = 0e2 = 0e3 = 0e4 = 0e5 = 1e6 = 0e7 = 0e8 = 0e9 = 0e10 = 0e11 = 0e12 = 0e13 = 0e14 = 0e15 = -1e16 = -1-0.032

6f1= 0f2 = 0f3 = 0f4 = 0f5 = 0f6 = -1f7 = -1 f8 = 0f9 = 0f10 = 0f11 = 0f12 = 0f13 = 0f14 = 0f15 = 0f16 = 10.005

Ss1 = 1s2 = 1s3 = 1s4 = 1s5 = 1s6 = 1s7 = -1s8 = -1s9 = -1s10 = -1s11 = -1s12 = 0s13 = 0s14 = 0s15 = 0s16 = 0

F = V12 + V22 + V32 + V42 +V52 + V62 V112 + V122 + V132 + V142 + V152 + V162U = F - 2 1f1 - 2 2f2 - 2 3f3 - 2 4f4 - 2 5f5 - 2 6f6 DETERMINACIN DE LAS ECUACIONES CORRELATIVAS

= 2V1 - 2 1 = 0 -- V1 = 1 = 2V2 - 2 1 = 0 -- V2 = 1

= 2V3 - 2 2 = 0 -- V3 = 2 = 2V4 2 4 = 0 -- V4 = 4

= 2V5 - 2 5 = 0 -- V5 = 5

= 2V6 + 2 6 = 0 -- V6 = - 6

= 2V7 + 2 6 = 0 -- V7 = - 6

= 2V8 + 2 4 = 0 -- V8 = - 4

= 2V9 + 2 3 = 0 -- V9 = - 3

= 2V10 + 2 3 = 0 -- V10 = - 3

= 2V11 + 2 2 = 0 -- V11 = - 2

= 2V12 + 2 1 2 2 = 0 -- V12 = - 1 + 2 = 2V13 + 2 2 2 3 = 0 -- V13 = 3 - 2

= 2V14 - 2 3 + 2 4 = 0 -- V14 = 3 4

= 2V15 - 2 4 + 2 5 = 0 -- V15 = 4 - 5

= 2V16 + 2 5 - 2 6 = 0 -- V16 = 6 - 5ECUACIONES NORMALES

Reemplazando los Vi en las ecuaciones condicionales:

3 1 - 12 + 0 3 + 0 4 + 0 5 + 0 6 = - 0.006

-1 1 + 4 2 - 1 3 + 0 4 + 0 5 + 0 6 = 0.022

0 1 - 1 2 + 4 3 - 1 4 + 0 5 + 0 6 = 0.018

0 1 + 0 2 - 1 3 + 4 4 - 1 5 + 0 6 = 0.042

0 1 + 0 2 + 0 3 - 1 4 + 3 5 - 1 6 = 0.0320 1 + 0 2 + 0 3 + 0 4 - 1 5 + 3 6 = -0.005

Resolviendo:

1 = 0.00082380

2 = 0.00847139

3 = 0.01106176

4 = 0.01777566

5 = 0.01804087

6 = 0.00434696

REEMPLAZANDO EN LAS ECUACIONES CORRELATIVAS:

V1 = 1 = 0.001

V2 = 1= 0.001

V3 = 2= 0.008

V4 = 4= 0.017

V5 = 5= 0.018

V6 = - 6= -0.004

V7 = - 6= -0.004

V8 = - 4= -0.017

V9 = - 3= -0.011

V10 = - 3= 0.011

V11 = - 2= -0.008

V12 = - 1 + 2= 0.008

V13 = 3 - 2= 0.003

V14 = 3 4= -0.007

V15 = 4 - 5= -0.000

V16 = 6 - 5= -0.014

TRAMOVCIRCUITO ICIRCUITO II CIRCUITO IIICIRCUITO IVCIRCUITO VCIRCUITO VIVALORES VCORREGIDOS

SIGNOVALORSIGNOVALORSIGNOVALORSIGNOVALORSIGNOVALORSIGNOVALOR

10.001+0.0010.001

20.001+0.0010.001

30.008+0.0080.008

40.017+0.0180.018

50.018+0.0180.018

6-0.004--0.004-0.004

7-0.004--0.005-0.005

80.017--0.0180.018

9-0.011--0.011-0.011

10-0.011--0.011-0.011

11-0.008--0.009-0.009

120.008-0.008+0.0080.008

130.003-0.003+0.0030.003

14-0.007+-0.007--0.007-0.007

150+0-00

16-0.014--0.014+-0.014-0.014

De la ecuacin del circuito = -0.006 = 0.022 = 0.018 = 0.042 = 0.032 = -0.005

Ec = 0.006Ec = -0.022Ec = -0.018Ec = -0.042Ec = -0.032Ec = 0.005

000000

DIFERENCIA DE NIVEL COMPENSADO

TRAMODIF. NIVELCORRECIONESDIFERENCIA DE NIVEL COMPENSADAS

10.893V1 = 0.001 0.894

29.125V2 = 0.0019.126

32.640V3 = 0.0082.648

4126.214V4 = 0.017126.231

540.628V5 = 0.01840.646

60.412V6 = -0.0040.408

70.399V7 = -0.0050.394

8164.388V8 = -0.018164.370

91.212V9 = -0.0111.201

106.999V10 = -0.0116.988

116.193V11 = -0.0096.184

1210.012V12 = 0.00810.020

136.481V13 = 0.0036.484

141.712V14 = -0.0071.705

1539.844V15 = 0.00039.844

160.816V16 = -0.0140.802

COTAS HALLADAS

PUNTOCOTA

A124.454

B134.474

C137.122

D263.353

E303.999

F303.591

G303.197

H138.827

I137.626

J130.638

SOLUCIN b:

Determinacin del nmero de Ecuaciones Condicionales (C)

C = #n - #S + #QC = 16 11 + 1C = 6 ec. Condicionales independientes.Ecuaciones Condicionales:

CIRCUITO I:

V1 + V2 V12 + 0.006 = 0 -- f1 = 0

CIRCUITO II:

V3 V11 + V12 V13 0.022 = 0 -- f2 = 0

CIRCUITO III:

-V9 V10 + V13 + V14 0.018 = 0 -- f3 = 0

CIRCUITO IV:

V4 V8 V14 + V15 0.042 = 0 -- f4 = 0

CIRCUITO V:

V5 V15 V16 0.032 = 0 -- f5 = 0

CIRCUITO VI:

-V6 V7 + V16 + 0.005 = 0 -- f6 = 0CUADRO RESUMEN DE LAS ECUACIONES CONDICIONALESV1V2V3V4V5V6V7V8V9V10V11V12V13V14V15V16K

L1 = 14L2 = 20L3 = 32L4 = 33L5 = 12 L6 = 16L7 = 15L8 = 26L9 = 5L10 = 22L11 = 26L12 = 9L13 = 12L14 = 17L15 = 17L16 = 14

1a1 = 1a2 = 1a3 = 0a4 = 0a5 = 0a6 = 0a7 = 0a8 = 0a9 = 0a10 = 0a11 = 0a12 = -1a13 = 0a14 = 0a15= 0a16 = 00.006

2b1=0b2 = 0b3 = 1b4 = 0b5 = 0b6 = 0b7 = 0b8 = 0b9 = 0b10 = 0b11 = -1b12 = 1b13 = -1b14 = 0b15 = 0b16 = 0-0.022

3c1 = 0c2 = 0c3 = 0c4 = 0c5 = 0c6 = 0c7 = 0c8 = 0c9 = -1c10 = -1c11 = 0c12 = 0c13 = 1c14 = 1c15 = 0c16 = 0-0.018

4d1 = 0d2 = 0d3 = 0d4 = 1d5 = 0d6 = 0d7 = 0d8= -1 d9 = 0d10 = 0d11 = 0d12 = 0d13 = 0d14 = -1d15 = 1d16 = 0-0.042

5e1 = 0e2 = 0e3 = 0e4 = 0e5 = 1e6 = 0e7 = 0e8 = 0e9 = 0e10 = 0e11 = 0e12 = 0e13 = 0e14 = 0e15 = -1e16 = -1-0.032

6f1= 0f2 = 0f3 = 0f4 = 0f5 = 0f6 = -1f7 = -1 f8 = 0f9 = 0f10 = 0f11 = 0f12 = 0f13 = 0f14 = 0f15 = 0f16 = 10.005

Ss1 = 1s2 = 1s3 = 1s4 = 1s5 = 1s6 = 1s7 = -1s8 = -1s9 = -1s10 = -1s11 = -1s12 = 0s13 = 0s14 = 0s15 = 0s16 = 0

ECUACIONES NORMALESReemplazando los Vi en las ecuaciones condicionales:

431 - 92 + 0 3 + 0 4 + 0 5 + 0 6 = - 0.006

-91 + 79 2 - 123 + 0 4 + 0 5 + 0 6 = 0.022

0 1 - 122 + 563 - 174 + 0 5 + 0 6 = 0.018

0 1 + 0 2 - 173 + 93 4 - 175 + 0 6 = 0.042

0 1 + 0 2 + 0 3 - 174 + 435 - 146 = 0.032

0 1 + 0 2 + 0 3 + 0 4 - 145 + 456 = - 0.005

Resolviendo:

1 = - 0.00006254 2 = 0.00036784 3 = 0.00063521 4 = 0.00077397 5 = 0.00112829

6 = 0.00023991

REEMPLAZANDO EN LAS ECUACIONES CORRELATIVAS:

V1 = 141 = - 0.001

V2 = 201= - 0.001

V3 = 322= 0.012

V4 = 334= 0.026

V5 = 125= 0.014

V6 = - 166= -0.004

V7 = - 156= -0.004

V8 = - 264= -0.020

V9 = - 53= -0.003

V10 = - 223= 0.014

V11 = - 262= -0.001

V12 = - 91 + 92= 0.004

V13 = 123 - 122= 0.004

V14 = 173 174= -0.002

V15 = 174 - 175= -0.006

V16 = 146 - 145= -0.012

VERIFICACIN DE LAS CORRECCIONES

TRAMOVCIRCUITO ICIRCUITO II CIRCUITO IIICIRCUITO IVCIRCUITO VCIRCUITO VIVALORES VCORREGIDOS

SIGNOVALORSIGNOVALORSIGNOVALORSIGNOVALORSIGNOVALORSIGNOVALOR

10.001+0.001-0.001

20.001+0.001-0.001

30.008+0.0110.012

40.017+0.0260.026

50.018+0.0140.013

6-0.004--0.003-0.004

7-0.004--0.004-0.004

80.017--0.0200.020

9-0.011--0.003-0.003

10-0.011--0.014-0.014

11-0.008--0.010-0.009

120.008-0.004+0.0040.004

130.003-0.003+0.0030.004

14-0.007+-0.002--0.002-0.002

150+-0.006--0.006-0.006

16-0.014--0.012+-0.012-0.013

De la ecuacin del circuito = -0.006 = 0.022 = 0.018 = 0.042 = 0.032 = -0.005

Ec = 0.006Ec = -0.022Ec = -0.018Ec = -0.042Ec = -0.032Ec = 0.005

000000

DIFERENCIA DE NIVEL COMPENSADO

TRAMODIF. NIVELCORRECIONESDIFERENCIA DE NIVEL COMPENSADAS

10.893V1 = - 0.001 0.892

29.125V2 = - 0.0019.124

32.640V3 = 0.0122.652

4126.214V4 = 0.026126.240

540.628V5 = 0.01340.641

60.412V6 = -0.0040.408

70.399V7 = -0.0040.395

8164.388V8 = -0.020164.368

91.212V9 = -0.0031.209

106.999V10 = -0.0146.985

116.193V11 = -0.0096.184

1210.012V12 = 0.00410.016

136.481V13 = 0.0046.485

141.712V14 = -0.0021.710

1539.844V15 = 0.00639.838

160.816V16 = -0.0130.803

COTAS HALLADAS

PUNTOCOTA

A124.456

B134.472

C137.124

D263.364

E304.005

F303.597

G303.202

H138.834

I137.625

J130.639

PROBLEMA 2.- En la siguiente red de nivelacin, determinar las cotas ortomtricas de los dems vrtices por mnimos cuadrados.

Determinacin del nmero de Ecuaciones Condicionales (C)

C = #n - #S + #QC = 13 8 + 2C = 7 ec. Condicionales independientes.Ecuaciones Condicionales:

CIRCUITO I:

V1 - V7 V8 + 0 = 0 -- f1 = 0

CIRCUITO II:

-V2 V7 + V9 + 0.01 = 0 -- f2 = 0

CIRCUITO III:

-V6 + V8 - V9 + V10 0.005 = 0 -- f3 = 0

CIRCUITO IV:

-V10 + V11 + V12 + 0.01 = 0 -- f4 = 0

CIRCUITO V:

-V3 V11 + V13 0.012 = 0 -- f5 = 0

CIRCUITO VI:

V4 + V5 - V12 V13 + 0.005 = 0 -- f6 = 0CIRCUITO VII:

V2 + V3 V4 V14 0.007 = 0 -- f7 = 0

CLCULO DE LOS COEFICIENTES DE LOS TRMINOS DE LAS ECUACIONES NORMALES

1234567KS

a1a1L1 = 4a1b1L1 = 0a1c1L1 = 0a1d1L1= 0a1e1L1= 0a1f1L1 = 0a1h1L1 = 0a1S1L1 = 3.9

a2a2L2 = 0a2b2L2 = 0a2c2L2 = 0a2d2L2 = 0a2e2L2 = 0a2f2L2 = 0a2h2L2 = 0a2S2L2 = 0

a3a3L3 = 0a3b3L3 = 0a3c3L3 = 0a3d3L3 = 0a3e3L3 = 0a3f3L3 = 0a3h3L3 = 0a3S3L3 = 0

a4a4L4 = 0a4b4L4 = 0a4c4L4 = 0a4d4L4 = 0a4e4L4 = 0a4f4L4 = 0a4h4L4 = 0a4S4L4 = 0

a5a5L5 = 0a5b5L5 = 0a5c5L5 = 0a5d5L5 = 0a5e5L5 = 0a5f5L5 = 0a5h5L5 = 0a5S5L5 = 0

a6a6L6 = 0a6b6L6 = 0a6c6L6 = 0a6d6L6 = 0a6e6L6 = 0a6f6L6 = 0a6h6L6 = 0a6S6L6 = 0

a7a7L7 = 4a7b7L7 = -4a7c7L7 = 0a7d7L7 = 0a7e7L7 = 0a7f7L7 = 0a7h7L7 = 0a7S7L7 = 0

a8a8L8 = 3a8b8L8 = 0a8c8L8 = -3a8d8L8 = 0a8e8L8 = 0a8f8L8 = 0a8h8L8 = 0a8S8L8 = 0

a9a9L9 = 0a9b9L9 = 0a9c9L9 = 0a9d9L9 = 0a9e9L9 = 0a9f9L9 = 0a9h9L9 = 0a9S9L9 = 0

a10a10L10 = 0a10b10L10 = 0a10c10L10 = 0a10d10L10 = 0a10e10L10 = 0a10f10L10 = 0a10h10L10 = 0a10S10L10 = 0

a11a11L11 = 0a11b11L11 = 0a11c11L11 = 0a11d11L11 = 0a11e11L11 = 0a11f11L11 = 0a11h11L11 = 0a11S11L11 = 0

a12a12L12 = 0a12b12L12 = 0a12c12L12 = 0a12d12L12 = 0a12e12L12 = 0a12f12L12 = 0a12h12L12 = 0a12S12L12 = 0

a13a13L13 = 0a13b13L13 = 0a13c13L13 = 0a13d13L13 = 0a13e13L13 = 0a13f13L13 = 0a13h13L13 = 0a13S13L13 = 0

a14a14L14 = 0a14b14L14 = 0a14c14L14 = 0a14d14L14 = 0a14e14L14 = 0a14f14L14 = 0a14h14L14 = 0a14S14L14 = 0

[aa] = 10.9[ab] = -4[ac] = -3[ad] = 0[ae] = 0[af] = 0[ah] = 00[aS] = 3.9

b1b1L1 = 0b1c1L1 = 0b1d1L1= 0b1e1L1= 0b1f1L1 = 0b1h1L1 = 0b1S1L1 = 0

b2b2L2 = 5b2c2L2 = 0b2d2L2 = 0b2e2L2 = 0b2f2L2 = 0b2h2L2 = -5b2S2L2 = 0

b3b3L3 = 0b3c3L3 = 0b3d3L3 = 0b3e3L3 = 0b3f3L3 = 0b3h3L3 = 0b3S3L3 = 0

b4b4L4 = 0b4c4L4 = 0b4d4L4 = 0b4e4L4 = 0b4f4L4 = 0b4h4L4 = 0b4S4L4 = 0

b5b5L5 = 0b5c5L5 = 0b5d5L5 = 0b5e5L5 = 0b5f5L5 = 0b5h5L5 = 0b5S5L5 = 0

b6b6L6 = 0b6c6L6 = 0b6d6L6 = 0b6e6L6 = 0b6f6L6 = 0b6h6L6 = 0b6S6L6 = 0

b7b7L7 = 4b7c7L7 = 0b7d7L7 = 0b7e7L7 = 0b7f7L7 = 0b7h7L7 = 0b7S7L7 = 0

b8b8L8 = 0b8c8L8 = -3b8d8L8 = 0b8e8L8 = 0b8f8L8 = 0b8h8L8 = 0b8S8L8 = 0

b9b9L9 = 2b9c9L9 = -2b9d9L9 = 0b9e9L9 = 0b9f9L9 = 0b9h9L9 = 0b9S9L9 = 0

b10b10L10 = 0b10c10L10 = 0b10d10L10 = 0b10e10L10 = 0b10f10L10 = 0b10h10L10 = 0b10S10L10 = 0

b11b11L11 = 0b11c11L11 = 0b11d11L11 = 0b11e11L11 = 0b11f11L11 = 0b11h11L11 = 0b11S11L11 = 0

b12b12L12 = 0b12c12L12 = 0b12d12L12 = 0b12e12L12 = 0b12f12L12 = 0b12h12L12 = 0b12S12L12 = 0

b13b13L13 = 0b13c13L13 = 0b13d13L13 = 0b13e13L13 = 0b13f13L13 = 0b13h13L13 = 0b13S13L13 = 0

b14b14L14 = 0b14c14L14 = 0b14d14L14 = 0b14e14L14 = 0b14f14L14 = 0b14h14L14 = 0b14S14L14 = 0

[ab] = -4[bb] = 11[bc] = -2[bd] = 0[be] = 0[bf] = 0[bh] = -50.1[bS] = 0

1234567KS

c1c1L1 = 0c1d1L1= 0c1e1L1= 0c1f1L1 = 0c1h1L1 = 0c1S1L1 = 0

c2c2L2 = 0c2d2L2 = 0c2e2L2 = 0c2f2L2 = 0c2h2L2 = 0c2S2L2 = 0

c3c3L3 = 0c3d3L3 = 0c3e3L3 = 0c3f3L3 = 0c3h3L3 = 0c3S3L3 = 0

c4c4L4 = 0c4d4L4 = 0c4e4L4 = 0c4f4L4 = 0c4h4L4 = 0c4S4L4 = 0

c5c5L5 = 0c5d5L5 = 0c5e5L5 = 0c5f5L5 = 0c5h5L5 = 0c5S5L5 = 0

c6c6L6 = 4c6d6L6 = 0c6e6L6 = 0c6f6L6 = 0c6h6L6 = 0c6S6L6 = 4

c7c7L7 = 0c7d7L7 = 0c7e7L7 = 0c7f7L7 = 0c7h7L7 = 0c7S7L7 = 0

c8c8L8 = 3c8d8L8 = 0c8e8L8 = 0c8f8L8 = 0c8h8L8 = 0c8S8L8 = 0

c9c9L9 = 2c9d9L9 = 0c9e9L9 = 0c9f9L9 = 0c9h9L9 = 0c9S9L9 = 0

c10c10L10 = 2c10d10L10 = -2c10e10L10 = 0c10f10L10 = 0c10h10L10 = 0c10S10L10 = 0

c11c11L11 = 0c11d11L11 = 0c11e11L11 = 0c11f11L11 = 0c11h11L11 = 0c11S11L11 = 0

c12c12L12 = 0c12d12L12 = 0c12e12L12 = 0c12f12L12 = 0c12h12L12 = 0c12S12L12 = 0

c13c13L13 = 0c13d13L13 = 0c13e13L13 = 0c13f13L13 = 0c13h13L13 = 0c13S13L13 = 0

c14c14L14 = 0c14d14L14 = 0c14e14L14 = 0c14f14L14 = 0c14h14L14 = 0c14S14L14 = 0

[aC] = -3[bc] = -2[cc] = 11[cd] = -2[ce] = 0[cf] = 0[ch] = 0-0.005[cS] = 4

d1d1L1= 0b1e1L1= 0b1f1L1 = 0b1h1L1 = 0b1S1L1 = 0

d2d2L2 = 0b2e2L2 = 0b2f2L2 = 0b2h2L2 = -5b2S2L2 = 0

d3d3L3 = 0b3e3L3 = 0b3f3L3 = 0b3h3L3 = 0b3S3L3 = 0

d4d4L4 = 0b4e4L4 = 0b4f4L4 = 0b4h4L4 = 0b4S4L4 = 0

d5d5L5 = 0b5e5L5 = 0b5f5L5 = 0b5h5L5 = 0b5S5L5 = 0

d6d6L6 = 0b6e6L6 = 0b6f6L6 = 0b6h6L6 = 0b6S6L6 = 0

d7d7L7 = 0b7e7L7 = 0b7f7L7 = 0b7h7L7 = 0b7S7L7 = 0

d8d8L8 = 0b8e8L8 = 0b8f8L8 = 0b8h8L8 = 0b8S8L8 = 0

d9d9L9 = 0b9e9L9 = 0b9f9L9 = 0b9h9L9 = 0b9S9L9 = 0

d10d10L10 = 2b10e10L10 = 0b10f10L10 = 0b10h10L10 = 0b10S10L10 = 0

d11d11L11 = 3b11e11L11 = -3b11f11L11 = 0b11h11L11 = 0b11S11L11 = 0

d12d12L12 = 2b12e12L12 = 0b12f12L12 = -2b12h12L12 = 0b12S12L12 = 0

d13d13L13 = 0b13e13L13 = 0b13f13L13 = 0b13h13L13 = 0b13S13L13 = 0

d14d14L14 = 0b14e14L14 = 0b14f14L14 = 0b14h14L14 = 0b14S14L14 = 0

++[ad] = 0[bd] = 0[cd] = -2[dd] = 7[de] = -3[df] = -2[dh] = 00.01[dS] = 0

1234567KS

e1e1L1= 0e1f1L1 = 0c1h1L1 = 0c1S1L1 = 0

e2e2L2 = 0e2f2L2 = 0c2h2L2 = 0c2S2L2 = 0

e3e3L3 = 5e3f3L3 = 0c3h3L3 = -5c3S3L3 = 0

e4e4L4 = 0e4f4L4 = 0c4h4L4 = 0c4S4L4 = 0

e5e5L5 = 4e5f5L5 = 0c5h5L5 = 0c5S5L5 = 5

e6e6L6 = 0e6f6L6 = 0c6h6L6 = 0c6S6L6 = 4

e7e7L7 = 0e7f7L7 = 0c7h7L7 = 0c7S7L7 = 0

e8e8L8 = 0e8f8L8 = 0c8h8L8 = 0c8S8L8 = 0

e9e9L9 = 0e9f9L9 = 0c9h9L9 = 0c9S9L9 = 0

e10e10L10 = 0e10f10L10 = 0c10h10L10 = 0c10S10L10 = 0

e11e11L11 = 3e11f11L11 = 0c11h11L11 = 0c11S11L11 = 0

e12e12L12 = 0e12f12L12 = 0c12h12L12 = 0c12S12L12 = 0

e13e13L13 = 4e13f13L13 = -4c13h13L13 = 0c13S13L13 = 0

e14e14L14 = 0e14f14L14 = 0c14h14L14 = 0c14S14L14 = 0

[ae] = 0[be] = 0[ce] = 0[de] = -3[ee] = 16[ef] = -4[eh] = -5-0.012[eS] = 4

f1f1L1 = 0f1h1L1 = 0f1S1L1 = 0

f2f2L2 = 0f2h2L2 = 0f2S2L2 = 0

f3f3L3 = 0f3h3L3 = 0f3S3L3 = 0

f4f4L4 = 5f4h4L4 = -5f4S4L4 = 0

f5f5L5 = 0f5h5L5 = 0f5S5L5 = 0

f6f6L6 = 0f6h6L6 = 0f6S6L6 = 0

f7f7L7 = 0f7h7L7 = 0f7S7L7 = 0

f8f8L8 = 0f8h8L8 = 0f8S8L8 = 0

f9f9L9 = 0f9h9L9 = 0f9S9L9 = 0

f10f10L10 = 0f10h10L10 = 0f10S10L10 = 0

f11f11L11 = 0f11h11L11 = 0f11S11L11 = 0

f12f12L12 = 2f12h12L12 = 0f12S12L12 = 0

f13f13L13 = 4f13h13L13 = 0f13S13L13 = 0

f14f14L14 = 0f14h14L14 = 0f14S14L14 = 0

[af] = 0[bf] = 0[cf] = 0[df] = -2[ef] = -4[ff] = 11[hf] = -50.005[fS] = 0

1234567KS

h1h1L1 = 0h1S1L1 = 0

h2h2L2 = 5h2S2L2 = 0

h3h3L3 = 5h3S3L3 = 0

h4h4L4 = 5h4S4L4 = 0

h5h5L5 = 0h5S5L5 = 5

h6h6L6 = 0h6S6L6 = 4

h7h7L7 = 0h7S7L7 = 0

h8h8L8 = 0h8S8L8 = 0

h9h9L9 = 0h9S9L9 = 0

h10h10L10 = 0h10S10L10 = 0

h11h11L11 = 0h11S11L11 = 0

h12h12L12 = 0h12S12L12 = 0

h13h13L13 = 0h13S13L13 = 0

h14h14L14 = 0h14S14L14 = 0

[ah] = 0[bh] = -5[ch] = 0[dh] = 0[eh] = -5[fh] = -5[hh] = 15-0.007[hS] = 0

ECUACIONES CORRELATIVAS

111 - 42 + 3 3 + 0 4 + 0 5 + 0 6 + 07 + 0 = 0

-41 + 11 2 - 23 + 0 4 + 0 5 + 0 6 - 5 7 + 0.01 = 0-3 1 - 22 + 113 - 24 + 0 5 + 0 6 + 0 7 - 0.005 = 0

0 1 + 0 2 - 23 + 7 4 - 35 - 2 6 + 0 7 + 0.01 = 0

0 1 + 0 2 + 0 3 - 34 + 165 - 46 - 5 7 - 0.012 = 0

0 1 + 02 + 0 3 - 24 - 45 + 116 - 5 7 + 0.005 = 0

0 1 - 52 + 0 3 + 04 - 55 - 56 + 15 7 - 0.007 = 0

Resolviendo:

1 = - 0.000438623 2 = -0.001091942 3 = -0.00013774 4 = -0.001507695 5 = 0.0003153987 = -0.000438623

DIFERENCIA DE NIVEL COMPENSADO

TRAMODIF. NIVELCORRECIONESDIFERENCIA DE NIVEL COMPENSADAS

16.480-0.00176.478

210.1650.005510.171

31.110-0.00161.108

42.408-0.00312.405

55.8750.00125.876

63.4800.00053.481

73.940-0.00263.937

82.5400.00092.541

96.235-0.00196.233

107.1700.00277.173

112.544-0.00552.539

124.636-0.00184.634

133.6420.00373.646

148.87408.874

COTAS HALLADAS

PUNTOCOTA

BM1100.002

A97.597

B101.243

C105.877

D98.706

E104.939

F102.398

BM2108.876