Ejercicio 3 Fase 4
2
3 EJERCICIO () = 2 − 1 2 ; () = 2 +2 a) ( + )(2) ( + )() = 2 − 1 2 +2 ( + )(2) = 2(2) − 1 2 = +2 2 +2= 4−1 2 +4+2= 3 2 +6= 12 + 3 2 = 15 2 b) ( − )(2) ( − )() = 2 − 2 2 − (− 2 + 2) ( − )() = 2 − 1 2 − 2 −2 ( − )(2) = 2(2) − 1 2 = −(2) 2 −2= 4−1 2 −4−2= 3 2 −6= 3 − 12 2 = −9 2 C) ( ∗ )(3) ( ∗ )() = ( 2 − 1 2 ) ( 2 + 2) ( ∗ )(3) = ( 2(3) − 1 2 ) (3 2 + 2) = ( 6−1 2 ) (9 + 2)=( 5 2 ) (11)= 55 2 d) ( ) (−3) ( ) ()= 2 − 1 2 2 +2 ( ) (−3)= 2(−3) − 1 2 −3 2 +2 = −6 − 1 2 6+2 = −8 2 8 = −8 16 = 1 2
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TRABAJO 3
Transcript of Ejercicio 3 Fase 4
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3 EJERCICIO
𝑓(𝑥) =2𝑥 − 1
2 ; 𝑔(𝑥) = 𝑥2 + 2
a) (𝑓 + 𝑔)(2)
(𝑓 + 𝑔)(𝑥) =2𝑥 − 1
2+ 2
(𝑓 + 𝑔)(2) =2(2) − 1
2= +22 + 2 =
4 − 1
2+ 4 + 2 =
3
2+ 6 =
12 + 3
2=
15
2
b) (𝑓 − 𝑔)(2)
(𝑓 − 𝑔)(𝑥) =2𝑥 − 2
2− (−𝑥2 + 2)
(𝑓 − 𝑔)(𝑥) =2𝑥 − 1
2− 𝑥2 − 2
(𝑓 − 𝑔)(2) =2(2) − 1
2= −(2)2 − 2 =
4 − 1
2− 4 − 2 =
3
2− 6 =
3 − 12
2=
−9
2
C) (𝑓 ∗ 𝑔)(3)
(𝑓 ∗ 𝑔)(𝑥) = (2𝑥 − 1
2) (𝑥2 + 2)
(𝑓 ∗ 𝑔)(3) = (2(3) − 1
2) (32 + 2) = (
6 − 1
2) (9 + 2) = (
5
2) (11) =
55
2
d) (𝑓
𝑔) (−3)
(𝑓
𝑔) (𝑥) =
2𝑥 − 12
𝑥2 + 2
(𝑓
𝑔) (−3) =
2(−3) − 12
−32 + 2
=
−6 − 12
6 + 2
=
−828
=−8
16=
1
2
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