VALIDASI NILAI TES

LAPORAN ASESMENT PSIKOLOGI TEKNIK TES

TES BAKAT DAN MINAT

Disusun untuk memenuhi tugas akhir semester 4 mata kuliah

Asesment psikologi teknik tes

Dosen Pengampuh: Mudhar, S.Psi, M.Si.

Disusun Oleh :

BK A1 2014

NUR ARIFAIZAL BASRI (14-500-0011)

PROGRAM STUDI BIMBINGAN DAN KONSELING

FAKULTAS KEGURUAN DAN ILMU PENDIDIKAN

UNIVERSITAS PGRI ADI BUANA SURABAYA

2016

HASIL TES DARI MAHASISWA PRODI MATEMATIKA

ANGKATAN 2015

TES PERSEPSI GAMBAR

RUANG DAN BIDANG

N = 20

∑ X = 78

∑ X2 = 404

No X X2

1 10 100

2 4 16

3 2 4

4 3 9

5 8 64

6 5 25

7 4 16

8 6 36

9 3 9

10 2 4

11 3 9

12 2 4

13 4 16

14 4 16

15 2 4

16 1 1

17 6 36

18 1 1

19 3 9

20 5 25

Jumlah 78 404

Mean = ∑X

N

= 78

20

= 3,9

SD = √N.∑(X2)−(∑X)2

N(N−1)

= √20.404−(78)2

20(20−1)

= √8080−6084

20.19

= √1996

380

= √5,25

= 2,29

SKALA 5

BS = 3,9 + (1,8 x 2,29) = 9,12 ke atas

B = 3,9 + (0,6 x 2,29) = 5,274

C = 3,9 - (0,6 x 2,29) = 2,526

K = 3,9 - (1,8 x 2,29) = -0,22

KS = Dibawah -0,22

DISTRAKTOR DAN VALIDITAS

Distraktor

Rangking 1-10

subyek 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 A D B E D D A A D D C D D B D C D A C B A

E E E E D E B A E D D C C B A B B C D D A

H A E B E E D A D A D A D D D C D D D A D

Q B E D B D A C D A B D D A D B E E B B A

F E B C B D A B A B C B B C D C A A D B A

T C D C D D B A E D A B B C E D B C B B A

B A E D D C B D C A C D A C A B D C A A C

G B E B B B A A C B C D D A D A A A C C A

M C C E D D A E A D C A A B B E E C E B A

N C C E D A A B E D A B A E E B D C B B A

Rangking 11-20

subyek 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

D E B E D E D C B C A A A B A D B C D D B

I E B E A B B A E D C A D D D A D D C A B

K A B E D A D A B E A D D D C B D B A A C

S B C E D D E C A E C A B B C E D B B A E

C A B E D D C C D A B D C C C D D B B B D

J B E E C E B A E D D D A D C A D C C C A

L A C E D A D D C C B B E D C B B B D E E

O A B E B D C A B E D A A E B E D B A E B

P C E D A B A E D C B B A D A B E C D D B

R A C D C A E C B D D A B B E D B C D A B

Subyek Nomer item

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

A D B E D D A A D D C D D B D C D A C B A

B A E D D C B D C A C D A C A B D C A A C

C A B E D D C C D A B D C C C D D B B B D

D E B E D E D C B C A A A B A D B C D D B

E E E E D E B A E D D C C B A B B C D D A

F E B C B D A B A B C B B C D C A A D B A

G B E B B B A A C B C D D A D A A A C C A

H A E B E E D A D A D A D D D C D D D A D

I E B E A B B A E D C A D D D A D D C A B

J B E E C E B A E D D D A D C A D C C C A

K A B E D A D A B E A D D D C B D B A A C

L A C E D A D D C C B B E D C B B B D E E

M C C E D D A E A D C A A B B E E C E B B

N C C E D A A B E D A B A E E B D C B B A

O A B E B D C A B E D A A E B E D B A E A

P C E D A B A E D C B B A D A B E C D D B

Q B E D B D A C D A B D D A D B E E B B A

R A C D C A E C B D D A B B E D B C D A B

S B C E D D E C A E C A B B C E D B B A E

T C D C D D B A E D A B B C E D B C B B A

Kunci B E E D E B A E D C D D A D A/C A A/D C C A

1. DISTRAKTOR

1

KET A B* C D E

Atas 2 2 3 1 2

Bawah 5 2 1 0 2

2

KET A B C D E*

Atas 0 2 2 1 5

Bawah 0 5 3 O 2

3

KET A B C D E*

Atas 0 2 2 2 4

Bawah 0 0 0 2 8

4

KET A B C D* E

Atas 0 2 0 6 1

Bawah 2 1 2 5 0

5

KET A B C D E*

Atas 1 1 1 5 2

Bawah 3 2 0 3 2

6

KET A B* C D E

Atas 6 3 0 1 0

Bawah 1 2 2 3 2

7

KET A* B C D E

Atas 5 2 1 1 1

Bawah 4 0 4 1 1

8

KET A B C D E*

Atas 2 0 2 3 3

Bawah 1 4 1 2 2

9

KET A B C D* E

Atas 3 2 0 4 0

Bawah 1 0 3 3 3

10

KET A B C* D E

Atas 2 1 5 2 0

Bawah 2 3 2 3 0

11

KET A B C D* E

Atas 2 3 1 4 0

Bawah 5 2 0 3 0

12

KET A B C D* E

Atas 3 2 3 4 0

Bawah 3 2 1 2 1

13

KET A* B C D E

Atas 2 3 3 0 1

Bawah 0 3 1 5 1

14

KET A B C D* E

Atas 2 4 0 5 2

Bawah 2 1 5 1 1

15

KET A* B C* D E

Atas 1 4 3 1 1

Bawah 2 3 0 3 2

16 KET A* B C D E

Atas 2 2 0 3 2

Bawah 0 3 0 6 1

17

KET A* B C D* E

Atas 3 0 5 1 1

Bawah 0 5 4 1 0

18

KET A B C* D E

Atas 1 3 2 2 1

Bawah 2 2 2 4 0

19

KET A B C* D E

Atas 2 6 1 1 0

Bawah 4 1 1 2 2

20

KET A* B C D E

Atas 8 0 1 1 0

Bawah 1 5 1 1 2

Kategori soal

P di atas 0,5 maka soal dikatakan mudah

P sama dengan 0,5 maka soal dikatakan sedang

P di bawah 0,5 maka soal dikatakan sulit

P1= 𝑩

𝐓 =

𝟒

𝟐𝟎 = 0,2 (Sukar) P8=

𝑩

𝐓 =

𝟓

𝟐𝟎 = 0,25 (Sukar) P15=

𝑩

𝐓 =

𝟔

𝟐𝟎 = 0,3 (Sukar)

A = Berfungsi D = Berfungsi A = Berfungsi C = Berfungsi B = Berfungsi E = Berfungsi

C = Berfungsi E = Berfungsi B = Berfungsi D = Berfungsi D = Berfungsi

P2= 𝑩

𝐓 =

𝟕

𝟐𝟎 = 0,35 (sukar) P9=

𝑩

𝐓 =

𝟕

𝟐𝟎 = 0,35 (Sukar) P16=

𝑩

𝐓 =

𝟐

𝟐𝟎 = 0,1 (Sukar)

A = Revisi C = Berfungsi A = Berfungsi C = Berfungsi B = Berfungsi D = Berfungsi

B = Berfungsi D = Berfungsi B = Berfungsi E = Berfungsi C = Revisi E = Berfungsi

P3= 𝑩

𝐓 =

𝟏𝟐

𝟐𝟎 = 0,6 (Sedang) P10=

𝑩

𝐓 =

𝟕

𝟐𝟎 = 0,35 (Sukar) P17=

𝑩

𝐓 =

𝟓

𝟐𝟎 = 0,25 (Sukar)

A = Revisi C = Berfungsi A = Berfungsi D = Berfungsi B = Berfungsi E = Berfungsi

B = Berfungsi D= Berfungsi B = Berfungsi E =Revisi C = Berfungsi

P4= 𝑩

𝐓 =

𝟏𝟏

𝟐𝟎 = 0,55 (Sedang) P11=

𝑩

𝐓 =

𝟕

𝟐𝟎 = 0,35 (Sukar) P18=

𝑩

𝐓 =

𝟒

𝟐𝟎 = 0,2 (Sukar)

A = Berfungsi C = Berfungsi A = Berfungsi C = Berfungsi A = Berfungsi D = Berfungsi

B = Berfungsi E = Berfungsi B = Berfungsi E =Revisi B = Berfungsi E = Berfungsi

P5= 𝑩

𝐓 =

𝟒

𝟐𝟎 = 0,2 (Sukar) P12=

𝑩

𝐓 =

𝟔

𝟐𝟎 = 0,3 (Sukar) P19=

𝑩

𝐓 =

𝟐

𝟐𝟎 = 0,1 (Sukar)

A = Berfungsi C = Berfungsi A = Berfungsi C = Berfungsi A = Berfungsi D = Berfungsi

B = Berfungsi D = Berfungsi B = Berfungsi E = Berfungsi B = Berfungsi E = Berfungsi

P6= 𝑩

𝐓 =

𝟓

𝟐𝟎 = 0,25 (Sukar) P13=

𝑩

𝐓 =

𝟐

𝟐𝟎 = 0,1 (Sukar) P20=

𝑩

𝐓 =

𝟗

𝟐𝟎 = 0,45 ( Sukar)

A = Berfungsi D = Berfungsi B = Berfungsi D = Berfungsi B = Berfungsi D = Berfungsi

C = Berfungsi E = Berfungsi C = Berfungsi E = Berfungsi C = Berfungsi E = Berfungsi

P7= 𝑩

𝐓 =

𝟗

𝟐𝟎 = 0,45 (sukar) P14=

𝑩

𝐓 =

𝟔

𝟐𝟎 = 0,3 (Sukar)

B = Berfungsi D = Berfungsi A = Berfungsi C = Berfungsi

C = Berfungsi E = berfungsi B = Berfungsi E = Berfungsi

2. Validasi

Item 1

r.xy= N.∑xy−(∑x)(∑y)

√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.15−(4)(78)

√{[20.(4)− (4)2][20.(404)−(78)2]}

= 300−312

√{[80− 16][8080−6084]}

= 12

√{[64][1996]}

= 12

√127744

= 12

357,41

= 0,33

Item 2


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.29−(7)(78)

√{[20.(7)− (7)2][20.(404)−(78)2]}

= 580−546

√{[140− 49][8080−6084]}

= 34

√{[91][1996]}

= 34

√18636

= 52

426,19

= 0,122

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 0 5 0 25 0

G 1 4 1 16 4

H 0 6 0 36 0

I 0 3 0 9 0

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 1 6 1 36 6

R 0 1 0 1 0

S 1 3 1 9 3

T 0 5 0 25 0

∑ 4 78 4 404 15

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 1 3 1 9 3

E 1 8 1 64 8

F 1 5 1 25 5

G 0 4 0 16 0

H 0 6 0 36 0

I 1 3 1 9 3

J 0 2 0 4 0

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 1 1 1 1 1

Q 1 6 1 36 6

R 0 1 0 1 0

S 1 3 0 9 3

T 0 5 0 25 0

∑ 7 78 6 404 29

Item 3


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.44−(12)(78)

√{[20.(12)− (12)2][20.(404)−(78)2]}

= 880−936

√{[240− 144][8080−6084]}

= −56

√{[96][1996]}

= −56

√191616

= −56

437,73

=-0,127

Item 4


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.48−(11)(78)

√{[20.(11)− (11)2][20.(404)−(78)2]}

= 960−858

√{[220− 121][8080−6084]}

= 102

√{[99][1996]}

= 102

√197604

= 102

444,52

= 0,22

S X Y X2 Y2 X.Y

A 1 10 100 100 10

B 0 4 0 16 0

C 1 2 1 4 2

D 1 3 1 9 3

E 1 8 1 64 8

F 0 5 0 25 0

G 0 4 0 16 0

H 0 6 0 36 0

I 1 3 1 9 3

J 1 2 1 4 2

K 1 3 1 9 3

L 1 2 1 4 2

M 1 4 1 16 4

N 1 4 1 16 4

O 1 2 1 4 2

P 1 1 0 1 1

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 12 78 11 404 44

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 1 4 1 16 4

C 1 2 1 4 2

D 1 3 1 9 3

E 1 8 1 64 8

F 0 5 0 25 0

G 0 4 0 16 0

H 0 6 0 36 0

I 0 3 0 9 0

J 0 2 0 4 0

K 1 3 1 9 3

L 1 2 1 4 2

M 1 4 1 16 4

N 1 4 1 16 4

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 1 3 1 9 3

T 1 5 1 25 5

∑ 11 78 11 404 48

Item 5


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.19−(4)(78)

√{[20.(4)− (4)2][20.(404)−(78)2]}

= 380−312

√{[80− 16][8080−6084]}

= 68

√{[64][1996]}

= 68

√127744

= 68

357,41

= 0,21

Item 6


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.20−(5)(78)

√{[20.(5)− (5)2][20.(404)−(78)2]}

= 400−390

√{[100− 25][8080−6084]}

= 10

√{[75][1996]}

= 10

√127744

= 10

357,41

= 0,27

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 1 3 1 9 3

E 1 8 1 64 8

F 0 5 0 25 0

G 0 4 0 16 0

H 1 6 1 36 6

I 0 3 0 9 0

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 4 78 4 404 19

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 1 4 1 16 4

C 0 2 0 4 0

D 0 3 0 9 0

E 1 8 1 64 8

F 0 5 0 25 0

G 0 4 0 16 0

H 0 6 0 36 0

I 1 3 1 9 3

J 1 2 1 4 2

K 1 3 0 9 3

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 5 78 4 404 20

Item 7


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.41−(9)(78)

√{[20.(9)− (9)2][20.(404)−(78)2]}

= 820−702

√{[180−81][8080−6084]}

= 118

√{[99][1996]}

= 118

√197604

= 118

444,52

= 0,26

Item 8


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.22−(5)(78)

√{[20.(5)− (5)2][20.(404)−(78)2]}

= 440−390

√{[100−25][8080−6084]}

= 50

√{[75][1996]}

= 50

√149700

= 50

386,91

= 0,129

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 1 8 1 64 8

F 0 5 0 25 0

G 1 4 1 16 4

H 1 6 1 36 6

I 1 3 1 9 3

J 1 2 1 4 2

K 1 3 1 9 3

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 1 2 1 4 2

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 1 3 0 9 3

T 0 5 0 25 0

∑ 9 78 8 404 41

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 1 8 1 64 8

F 0 5 0 25 0

G 0 4 0 16 0

H 0 6 0 36 0

I 1 3 1 9 3

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 1 4 1 16 4

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 1 5 1 25 5

∑ 5 78 5 404 22

Item 9


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.36−(7)(78)

√{[20.(7)− (7)2][20.(404)−(78)2]}

= 720−546

√{[140−49][8080−6084]}

= 174

√{[91][1996]}

= 174

√181636

= 174

426,21

= 0,41

Item 10


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.31−(7)(78)

√{[20.(7)− (7)2][20.(404)−(78)2]}

= 620−546

√{[140−49][8080−6084]}

= 74

√{[91][1996]}

= 74

√181636

= 74

426,21

= 0,12

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 1 8 1 64 8

F 0 5 0 25 0

G 0 4 0 16 0

H 0 6 0 36 0

I 1 3 1 9 3

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 1 4 1 16 4

N 1 4 1 16 4

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 1 1 0

S 0 3 0 9 0

T 1 5 1 25 5

∑ 7 78 8 404 36

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 1 4 1 16 4

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 1 5 1 25 5

G 1 4 1 16 4

H 0 6 0 36 0

I 1 3 1 9 3

J 0 2 0 4 0

K 0 3 0 9 0

L 0 2 0 4 0

M 1 4 1 16 4

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 1 1 1 1 1

S 0 3 1 9 0

T 0 5 0 25 0

∑ 7 78 8 404 31

Item 11


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.31−(7)(78)

√{[20.(7)− (7)2][20.(404)−(78)2]}

= 620−546

√{[140−49][8080−6084]}

= 74

√{[91][1996]}

= 74

√181636

= 74

426,198

= 0,23

Item 12


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.32−(6)(78)

√{[20.(6)− (6)2][20.(404)−(78)2]}

= 640−468

√{[120−36][8080−6084]}

= 172

√{[84][1996]}

= 172

√167664

= 172

409,46

= 0,42

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 1 4 1 16 4

C 1 2 1 4 2

D 0 3 0 9 0

E 0 8 0 64 0

F 0 5 0 25 0

G 1 4 1 16 4

H 0 6 0 36 0

I 0 3 0 9 0

J 1 2 1 4 2

K 1 3 1 9 3

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 1 6 1 36 6

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 7 78 7 404 31

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 0 5 0 25 0

G 1 4 1 16 4

H 1 6 1 36 6

I 1 3 1 9 3

J 0 2 0 4 0

K 1 3 1 9 3

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 1 6 1 36 6

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 6 78 6 404 32

Item 13


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.10−(2)(78)

√{[20.(2)− (2)2][20.(404)−(78)2]}

= 200−156

√{[40−4][8080−6084]}

= 44

√{[160][1996]}

= 44

√319360

= 44

565,11

= 0,077

Item 14


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.34−(6)(78)

√{[20.(6)− (6)2][20.(404)−(78)2]}

= 680−468

√{[120−36][8080−6084]}

= 212

√{[84][1996]}

= 212

√167664

= 212

409,51

= 0,52

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 0 5 0 25 0

G 1 4 1 16 4

H 0 6 0 36 0

I 0 3 0 9 0

J 0 2 0 4 0

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 1 6 1 36 6

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 2 78 2 404 10

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 1 5 1 25 5

G 1 4 1 16 4

H 1 6 1 36 6

I 1 3 1 9 3

J 0 2 0 4 0

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 1 6 1 36 6

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 6 78 6 404 34

Item 15


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.30−(6)(78)

√{[20.(6)− (6)2][20.(404)−(78)2]}

= 600−468

√{[120−36][8080−6084]}

= 132

√{[84][1996]}

= 132

√167664

= 132

409,58

= 0,322

Item 16


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.9−(2)(78)

√{[20.(2)− (2)2][20.(404)−(78)2]}

= 180−156

√{[400−4][8080−6084]}

= 24

√{[396][1996]}

= 24

√790416

= 24

889,1

= 0,27

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 1 5 1 25 5

G 1 4 1 16 4

H 1 6 1 36 6

I 1 3 1 9 3

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 6 78 6 404 30

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 1 5 1 25 5

G 1 4 1 16 4

H 0 6 0 36 0

I 0 3 0 9 0

J 0 2 0 4 0

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 2 78 2 404 9

Item 17


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.28−(5)(78)

√{[20.(5)− (5)2][20.(404)−(78)2]}

= 560−390

√{[100−25][8080−6084]}

= 170

√{[75][1996]}

= 170

√149700

= 170

386,91

= 0,43

Item 18


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.19−(4)(78)

√{[20.(4)− (4)2][20.(404)−(78)2]}

= 380−312

√{[80−16][8080−6084]}

= 68

√{[64][1996]}

= 68

√127744

= 68

357,41

= 0,22

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 1 5 1 25 5

G 1 4 1 16 4

H 1 6 1 36 6

I 1 3 1 9 3

J 0 2 0 4 0

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 5 78 5 404 28

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 0 5 0 25 0

G 1 4 1 16 4

H 0 6 0 36 0

I 1 3 1 9 3

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 4 78 4 404 19

Item 19


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.6−(2)(78)

√{[20.(2)− (2)2][20.(404)−(78)2]}

= 120−156

√{[120−4][8080−6084]}

= −36

√{[116][1996]}

= −36

√231536

= −36

481,181

= -0,07

Item 20


√{[N.(∑X2)− (∑X)2][N.(∑Y2)−(∑Y)2]}

= 20.46−(9)(78)

√{[20.(9)− (9)2][20.(404)−(78)2]}

= 920−702

√{[180−81][8080−6084]}

= 218

√{[99][1996]}

= 218

√197604

= 218

444,52

= 0,49

S X Y X2 Y2 X.Y

A 0 10 0 100 0

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 0 8 0 64 0

F 0 5 0 25 0

G 1 4 1 16 4

H 0 6 0 36 0

I 0 3 0 9 0

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 0 4 0 16 0

O 0 2 0 4 0

P 0 1 0 1 0

Q 0 6 0 36 0

R 0 1 0 1 0

S 0 3 0 9 0

T 0 5 0 25 0

∑ 2 78 2 404 6

S X Y X2 Y2 X.Y

A 1 10 1 100 10

B 0 4 0 16 0

C 0 2 0 4 0

D 0 3 0 9 0

E 1 8 1 64 8

F 1 5 1 25 5

G 1 4 1 16 4

H 0 6 0 36 0

I 0 3 0 9 0

J 1 2 1 4 2

K 0 3 0 9 0

L 0 2 0 4 0

M 0 4 0 16 0

N 1 4 1 16 4

O 1 2 1 4 2

P 0 1 0 1 0

Q 1 6 1 36 6

R 0 1 0 1 0

S 0 3 0 9 0

T 1 5 1 25 5

∑ 9 78 9 404 46

KUNCI JAWABAN TES PERSEPSI GAMBAR RUANG DAN BIDANG

1. B 11. D

2. E 12. D

3. E 13. A

4. D 14. D

5. E 15. A/C

6. B 16. A

7. A 17. A/D

8. E 18. C

9. D 19. C

10. C 20. A

VALIDASI NILAI TES

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