Escalera
4
DISEÑO DE ESCALERAS Diseñar por flexion el momento positivo de diseño. ancho= 1.60 m p= 0.30 s/c = 600 kg/m2 n° d pasos= 7 f'c = 280 kg/cm2 Ƴconcreto = 2.4 t/m3 fy = 4200 kg/cm2 0.17 0.18 cm 0.17 cm 0.25 1.60 7 pasos @ 0.30 0.40 t= Ln ≈ Ln ; 3.70 = 0.148 = 3.70 = 0.185 usar = 25 20 25 20 30 30 0.8575 324 + 900 34.98571137 θ= arctg( θ= 0.54 hm = 17 + 18 = 28.41 cm cos (θ) 2 METRADO DE CARGAS P.P. = 0.28 x 1.60 x 2.4 x 1.4 = 1.527 t/m acabado= 0.10 x 1.60 x 2.4 x 1.4 = 0.538 t/m s/c = 0.6 x 1.60 x 1.7 = 1.632 t/m Wu2 = 3.4 t/m P.P = 0.17 x 1.60 x 2.4 x 1.4 0.914 t/m Wu2 = 2.76 t/m 4.025 x RB = 22.36 + 4.232 RB = 6.606 tn 3.40 2.76 cos (θ)= Muro portante de albañileria
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Transcript of Escalera
Hoja1DISEO DE ESCALERASDisear por flexion el momento positivo de diseo.ancho=1.60 mp=0.30s/c =600 kg/m2n d pasos=7f'c =280 kg/cm2concreto =2.4t/m3fy =4200 kg/cm2
0.17
0.18 cm
0.17 cm
0.70
0.251.607 pasos @ 0.300.40t=LnLn;3.70=0.148=3.70=0.185usar =0.17 cm25202520cos ()=30300.8575324+90034.9857113691=arctg(CP/P)=0.54hm =17+18=28.41 cmcos ()2METRADO DE CARGAS
P.P. = 0.28x1.60x2.4x1.4=1.5274390908t/macabado=0.10x1.60x2.4x1.4=0.5376t/ms/c =0.6x1.60x1.7=1.632t/mWu2=3.4t/mP.P =0.17 x1.60x2.4x1.40.91392t/mWu2=2.76t/m
4.025x RB=22.3568625+4.232RB =6.6059285714tn3.402.76
1.7252.30RAXRBVx =RB-Wu2 Xo =0Xo =1.94 m2Mu max =6.6059285714x1.94-3.4x1.94=6.4173959251t-m2Mu dis =Mu max = 5.13t-m 1/2: d =14.02cma=2cmAs =513391.67400960410.44cm249196.7a=43.82905826691.53cm28.56
Muro portante de albaileria
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