CEE110_PS5_2016

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    CEE 110 Probability and Statistics for EngineersProblem Set 5

    Due Thursday of Week 7, 10 a.m.

    Read sections 8-1, 8-2, and 8-4, and comp ete!

    8-4, 8-12, 8-14, 8-17, 8-2", 8-40, 8-#1, 8-#"

    $ractice pro% ems &p ease re'ie()!

    8-" a) *amp e mean from the +rst con+dence inter'a 8.02 ./8-8.02) 2 "0

    *amp e mean from the second con+dence inter'a /./" .0"-/./") 2 "0

    %) The /" 3 is & 8.02, #1./8) and the /0 3 is & /./", #0.0"). Thehi her the con+dence

    e'e , the (ider the 3.

    8-11 /" T(o-sided 3 on the true mean yie d! (here 5 /0.480, σ ,n " and 6 0.02" 1./#

    11.9385.875/)3(96.1480.905/)3(96.1480.90

    // 025.0025.0

    ≤≤

    +≤≤−

    +≤≤−

    µ

    µ

    σ µ σ n z xn z x

    8-1 a) // T(o-sided 3 on the true mean piston rin diameter or α 0.01, 6 α 2 6 0.00" 2."8 , and 5 74.0 #, σ 0.001, n 1"

    x z

    nx z

    n−

    ≤ ≤ +

    0 005 0 005. .σ µ σ

    74036 258

    0001

    1574036 258

    0001

    15. .

    .. .

    .−

    ≤ ≤ +

    µ

    74.0 " ≤ µ ≤ 74.0 #7

    %) // ne-sided 3 on the true mean piston rin diameteror α 0.01, 6 α 6 0.01 2. and 5 74.0 #, σ 0.001, n 1"

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    787.225,005.0 =t 385.330,001.0 =t

    8- / a) The data appear to %e norma y distri%uted %ased on e5amination ofthe norma pro%a%i ity p ot %e o(.

    %) /" t(o-sided con+dence inter'a on mean comprehensi'e stren th

    35.62259.912 === s xn 201.211,025.0 =t

    5.22823.223712

    6.35201.29.2259

    12

    6.35201.29.2259

    11,025.011,025.0

    ≤≤

    +≤≤

    +≤≤

    µ

    µ

    µ n

    st x

    n

    st x

    c) /" o(er-con+dence %ound on mean stren th

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    µ

    µ

    µ

    4.2241

    12

    6.35796.19.2259

    11,05.0n

    st x

    8-#2 a) /" on+dence 3nter'a on the death rate from un cancer.

    823.01000823ˆ == p

    1000=n 96.12/ =α z

    8467.07993.01000

    )177.0(823.096.1823.0

    1000)177.0(823.0

    96.1823.0

    )ˆ1(ˆˆ)ˆ1(ˆˆ 2/2/

    ≤≤

    +≤≤−

    −+≤≤−−

    p

    p

    n p p

    z p pn

    p p z p α α

    %) 9 0.0 , α 0.0", 6 α 2 6 0.02" 1./# and p 0.82 as the initiaestimate of p,

    79.621)823.01(823.003.096.1

    )ˆ1(ˆ22

    2/ =−

    =−

    = p p E

    z n α

    ,n ≅ #22.

    c) 9 0.0 , α 0.0", 6 α 2 6 0.02" 1./# at east /" con+dent

    11.1067)25.0(03.096.1

    )25.0(22

    2/ =

    =

    = E

    z n α

    ,n ≅ 10#8.

    8-## 9 0.017, α 0.01, 6 α 2 6 0.00" 2."8

    13.5758)5.01(5.0017.0

    58.2

    )1(

    222/

    =−

    =−

    = p p E z

    n α

    , n ≅ "7"/