Report - SOLUCIONES Hoja 2 de Problemas 1.- · Hacemos un nuevo cambio v u = z → v = zu→ v(1 = uz(1 +z por lo tanto v(1 = − 12 +5 v u 5+2 v u → uz(1 +z = − 12 + 5z 5+2z → uz(1

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