TALLER DE ESTADISTICA

MATEMATICAS VTALLER 1

PARTICIPANTES,JHON SILVA DIEGO GUERRERO

ESCUELA COLOMBIANA DE CARRERAS INDUSTRIALES.BOGOTA 7 DE OCTUBRE DE 20101. La siguiente tabla muestra las alturas de 100 estudiantes de la universidad ECCIALTURAESTUDIANTESXiXi * fiXi-xfi(Xi-x)2

60-63561,5307,5-6,45208,1

63-661864,51161-3,45214,25

66-694267,52835-0,458,51

69-722770,51903,52,55175,57

72-75873,55885,55246,42

TOTAL1006795-2,258,78

A. 6795 = 67,95 Xi-67,95 = 0,0225100 100

B. fi (Xi - )2 = (8,78) 878 = 8,61 n-1 99 99

Varianza estndar 8,61 = 2,9349

C. +- 1,5 * 5 = 67,95 +- 1,5 * (2,93,49)63,547567,95 +- 4,402572,3525

Chebyshev 1-1 = 1- 1 = 0,55 = 55,6% K2 (1,5)22. visitas%acumulativa% acumulativo

381,62%381,62%

401,70%783,32%

411,74%1195,06%

451,91%1646,98%

482,04%2129,02%

482,04%26011,06%

502,13%31013,19%

502,13%36015,32%

512,17%41117,49%

512,17%46219,66%

522,21%51421,87%

522,21%56624,09%

532,26%61926,34%

542,30%67328,64%

552,34%72830,98%

552,34%78333,32%

552,34%83835,66%

562,38%89438,04%

562,38%95040,43%

572,43%100742,85%

592,51%106645,36%

592,51%112547,87%

592,51%118450,38%

622,64%124653,02%

622,64%130855,66%

622,64%137058,30%

632,68%143360,98%

642,72%149763,70%

652,77%156266,47%

662,81%162869,28%

662,81%169472,09%

672,85%176174,94%

672,85%182877,79%

692,94%189780,72%

692,94%196683,66%

713,02%203786,68%

773,28%211489,96%

783,32%219293,28%

793,36%227196,64%

793,36%2350100,00%

A. la mediana del nmero de llamadas es (57 +59)/2 = 58 llamadasB. Q1 = L25 40 + 1 (25/100) = 10.2510 511 (0,25)11 52 Q1 = 51 + 0,25 = 51,25

Q3 = L75 40 + 1 (75/100) = 10.2530 6666,7531 66 Q3 = 66 + 0,75 = 66,75

D. el primer decil.

D1 = 40 (1/40) =44 45

D9 = 40 (9/40) = 3636 71

E. El centil 33 y el 82P33 = (2350 * 33)/100 = 775,5P33 = 55 + ((775.5 - 728)/55) = 817,26P33 = 55P82 = (2350 * 82)/100 = 1927P82 = 69 + ((1927 - 1897)/69) = 1968P82 = 71

4. Q1 = L25 = 28 + 1 (25/100) = 7,25Dato 7 = 209(209+229)/2 = 219 = Q1Dato 8 = 229

Q3 = L75 = 28 + 1 (75/100) = 21,75Dato 21 = 296(296+307)/2 = 301 = Q3Dato 22 = 307 Mediana = (246 + 260)/2 = 253

116253

Q1Q3

La forma de distribucin del sesgo es negativa por que la mayora de datos atpicos se encuentran en el primer cuartil.

90 %1 - (1)/K = 0,9Despeje K2 = 1/1 * 0.9 = K = 3,160,9 (28) = 25,2 = 25 hospitales. = 253

S2 = (Xi - )2 /n-1 = 89000/27 = 3296.29 = S2

S = 3296.29 = 57,41

253 +3,16 (57,41) = 434,42253 -3,16 (57,41) = 71,58