Practica 3

9
ESTANDARIZADO MAX 12x1+5x2+15x3+10x4+0S1+0S2+0S3+0S4+0S5+0S6+0S7-Ma1-Ma ST x1+x2+9x3+12x4+S1=1500 2x1+3x2+4x3+x4+S2=1000 x1+2x2+5x3+10x4+S3=800 X1-S4+a1=40 X2-S5+a2=130 X3-S6+a3=30 X4+S7=10 PRIMERO: VARIABLES DE DECISIÓN V.B X1 X2 X3 X4 S1 S1 5 1 9 12 1 S2 2 3 4 1 0 S3 3 2 5 10 0 a1 1 0 0 0 0 a2 0 1 0 0 0 a3 0 0 1 0 0 S7 0 0 0 1 0 Z -12 -5 -15 -10 0 -9 S1 5 1 5 12 1 -4 S2 2 3 0 1 0 -5 S3 3 2 0 10 0 0 a1 1 0 0 0 0 0 a2 0 1 0 0 0 -1 X3 0 0 1 0 0 0 S7 0 0 0 1 0 15 Z -12 -5 0 -10 0 -5 S1 0 1 5 12 1 -2 S2 0 3 0 1 0 -3 S3 0 2 0 10 0 -1 X1 1 0 0 0 0 0 a2 0 1 0 0 0 0 X3 0 0 1 0 0 0 S7 0 0 0 1 0 12 Z 0 -5 0 -10 0 -12 S1 0 1 5 0 1 -1 S2 0 3 0 0 0 -10 S3 0 2 0 0 0 0 X1 1 0 0 0 0 0 a2 0 1 0 0 0 0 X3 0 0 1 0 0

description

INVESTIGACIÓN DE OPERACIONES

Transcript of Practica 3

Page 1: Practica 3

ESTANDARIZADOMAX 12x1+5x2+15x3+10x4+0S1+0S2+0S3+0S4+0S5+0S6+0S7-Ma1-Ma2-Ma3ST

5x1+x2+9x3+12x4+S1=1500 2x1+3x2+4x3+x4+S2=1000

3x1+2x2+5x3+10x4+S3=800 X1-S4+a1=40

X2-S5+a2=130X3-S6+a3=30

X4+S7=10

PRIMERO:VARIABLES DE DECISIÓN VARIABLES DE HOLGURA

V.B X1 X2 X3 X4 S1 S2S1 5 1 9 12 1 0S2 2 3 4 1 0 1S3 3 2 5 10 0 0a1 1 0 0 0 0 0a2 0 1 0 0 0 0a3 0 0 1 0 0 0S7 0 0 0 1 0 0

Z -12 -5 -15 -10 0 0-9 S1 5 1 5 12 1 0-4 S2 2 3 0 1 0 1-5 S3 3 2 0 10 0 00 a1 1 0 0 0 0 00 a2 0 1 0 0 0 0

-1 X3 0 0 1 0 0 00 S7 0 0 0 1 0 0

15 Z -12 -5 0 -10 0 0-5 S1 0 1 5 12 1 0-2 S2 0 3 0 1 0 1-3 S3 0 2 0 10 0 0-1 X1 1 0 0 0 0 00 a2 0 1 0 0 0 00 X3 0 0 1 0 0 00 S7 0 0 0 1 0 0

12 Z 0 -5 0 -10 0 0-12 S1 0 1 5 0 1 0

-1 S2 0 3 0 0 0 1-10 S3 0 2 0 0 0 0

0 X1 1 0 0 0 0 00 a2 0 1 0 0 0 00 X3 0 0 1 0 0 0

Page 2: Practica 3

-1 X4 0 0 0 1 0 010 Z 0 -5 0 0 0 0-1 S1 0 0 5 0 1 0-3 S2 0 0 0 0 0 1-2 S3 0 0 0 0 0 00 X1 1 0 0 0 0 0

-1 X2 0 1 0 0 0 00 X3 0 0 1 0 0 00 X4 0 0 0 1 0 05 Z 0 0 0 0 0 0

-4 S1 0 0 5 0 1 0-4 S2 0 0 0 0 0 1-5 S6 0 0 0 0 0 00 X1 1 0 0 0 0 00 X2 0 1 0 0 0 01 X3 0 0 1 0 0 00 S7 0 0 0 1 0 0

15 Z 0 0 0 0 0 04 S1 0 0 5 4 1 0

-7 S2 0 0 0 -7 0 12 S4 0 0 0 2 0 00 X1 1 0 0 0 0 00 X2 0 1 0 0 0 02 X3 0 0 1 2 0 0

-1 X4 0 0 0 1 0 020 Z 0 0 0 20 0 0

-2.6 S1 0 0 5 -4.66666667 1 00.4 S2 0 0 0 -5.66666667 0 1

-0.6 S4 0 0 0 3.33333333 0 01 X1 1 0 0 3.33333333 0 00 X2 0 1 0 0 0 0

-0.6 X3 0 0 1 0 0 00 X4 0 0 0 1 0 03 Z 0 0 0 30 0 0

RESPUESTA:

LA SOLUCIÓN ÓPTIMA ES:

X1= 130X2= 130X3= 30X4= 10Z= 2660

Page 3: Practica 3

FILA/COLUMNA PIVOTPIVOT

EX FILA PIVOTRESPUESTA

VARIABLES DE HOLGURA VARIABLES ARTIFICIALES

S3 S4 S5 S6 S7 a1 a2 a30 0 0 0 0 0 0 00 0 0 0 0 0 0 01 0 0 0 0 0 0 00 -1 0 0 0 1 0 00 0 -1 0 0 0 1 00 0 0 -1 0 0 0 10 0 0 0 1 0 0 00 0 0 0 0 1000 1000 10000 0 0 4 0 0 0 -40 0 0 4 0 0 0 -41 0 0 5 0 0 0 -50 -1 0 0 0 1 0 00 0 -1 0 0 0 1 00 0 0 -1 0 0 0 10 0 0 0 1 0 0 00 0 0 -15 0 1000 1000 10150 5 0 4 0 -5 0 -40 2 0 4 0 -2 0 -41 3 0 5 0 -3 0 -50 -1 0 0 0 1 0 00 0 -1 0 0 0 1 00 0 0 -1 0 0 0 10 0 0 0 1 0 0 00 -12 0 -15 0 1012 1000 10150 5 0 4 -12 -5 0 -40 2 0 4 -1 -2 0 -41 3 0 5 -10 -3 0 -50 -1 0 0 0 1 0 00 0 -1 0 0 0 1 00 0 0 -1 0 0 0 1

Page 4: Practica 3

0 0 0 0 1 0 0 00 -12 0 -15 10 1012 1000 10150 5 1 4 -12 -5 -1 -40 2 3 4 -1 -2 -3 -41 3 2 5 -10 -3 -2 -50 -1 0 0 0 1 0 00 0 -1 0 0 0 1 00 0 0 -1 0 0 0 10 0 0 0 1 0 0 00 -12 -5 -15 10 1012 1005 1015

-0.8 2.6 -0.6 0 -4 -2.6 0.6 0-0.8 -0.4 1.4 0 7 0.4 -1.4 00.2 0.6 0.4 1 -2 -0.6 -0.4 -1

0 -1 0 0 0 1 0 00 0 -1 0 0 0 1 0

0.2 0.6 0.4 0 -2 -0.6 -0.4 00 0 0 0 1 0 0 03 -3 1 0 -20 1003 999 1000

-0.8 2.6 -0.6 0 0 -2.6 0.6 0-0.8 -0.4 1.4 0 0 0.4 -1.4 00.2 0.6 0.4 1 0 -0.6 -0.4 -1

0 -1 0 0 0 1 0 00 0 -1 0 0 0 1 0

0.2 0.6 0.4 0 0 -0.6 -0.4 00 0 0 0 1 0 0 03 -3 1 0 0 1003 999 1000

-1.66666667 0 -2.33333333 -4.33333333 0 0 2.33333333 4.33333333-0.66666667 0 1.66666667 0.66666667 0 0 -1.66666667 -0.666666670.33333333 1 0.66666667 1.66666667 0 -1 -0.66666667 -1.666666670.33333333 0 0.66666667 1.66666667 0 0 -0.66666667 -1.66666667

0 0 -1 0 0 0 1 00 0 0 -1 0 0 0 10 0 0 0 1 0 0 04 0 3 5 0 1000 997 995

Page 5: Practica 3

b Ɵ1500 166.66671000 250.0000

800 160.000040 INFINITO I

130 INFINITO30 30.000010 INFINITO

01380 276

880 440650 216.6666667

40 40 II130 INFINITO

30 INFINITO10 INFINITO

4501180 98.33333333

800 800530 53 III

40 INFINITO130 INFINITO

30 INFINITO10 10

9301060 1060

790 263.3333333430 215 IV

40 INFINITO130 130

30 INFINITO

Page 6: Practica 3

10 INFINITO1030

930 232.5400 100170 34

40 INFINITO V130 INFINITO

30 -3010 INFINITO

1680794 -198.5264 37.71428571

34 -1740 INFINITO VI

130 INFINITO64 -3210 10

2190834 320.7692308194 -485

54 9040 -40 VII

130 INFINITO84 14010 INFINITO

2390600230

90 150130 VIII130

3010

2660

Page 7: Practica 3

MIN Z=5A+8B+0S1+0S2+0S3-MA1-MA2-MA3 Reglas de aumentoST Tipo

4A+10B-S1+A1=40 Restricción10A+5B-S2+A2=50 <=7Q+7B-S3+A3=49 >=

=

Reglas de aumento en la F.O.

VariableAgregada

+Si -Si +Ai

VARIABLES DE DECISIÓN VARIABLES DE HOLGURA

VB A B S1 S2A1 4 10 -1 0A2 10 5 0 -1A3 7 7 0 0Z -5 -8 0 0

-4 A1 0 8 -1 0.4-10 A2 1 0.5 0 -0.1

-7 A 0 3.5 0 0.75 Z 0 -5.5 0 -0.5

-8 B 0 1 -0.125 0.05-0.5 A2 1 0 0.0625 -0.125-3.5 A 0 0 0.4375 0.5255.5 Z 0 0 -0.6875 -0.225

BA2A3Z

Page 8: Practica 3

Reglas de aumentoVariablesagregadas

+Si Variable de holgura -Si +Ai Variable de exceso + Variable artificial

+Ai Variable artificial

Reglas de aumento en la F.O.

Funcion Objetivo * tiene infinitas soluciones*Max Min 0Si 0Si 0Si 0Si

-MAi +MAi

VARIABLES DE HOLGURA VARIABLES ARTIFICIALES

S3 A1 A2 A3 b Ɵ0 1 0 0 40 100 0 1 0 50 5 I

-1 0 0 1 49 70 1000 1000 1000 00 1 -0.4 0 20 2.50 0 0.1 0 5 10 II

-1 0 -0.7 1 14 40 1000 1000.5 1000 250 0.125 -0.05 0 2.5 500 -0.0625 0.125 0 3.75 -30 III

-1 -0.4375 -0.525 1 5.25 100 1000.6875 1000.225 1000 38.75

IV