ejercicio 211 libro de baldor
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Transcript of ejercicio 211 libro de baldor
POTENCIAS
EJERCICIOS DE BLADOR “211”
3. (x2 + y
3 )
6 = (x
2)
6 + 6 (x
2)
5(y
3) + 15(x
2)
4 (y
3)
2 + 20 (x
2)
3 (y
3)3 + 15 (x
2)
2 (y
3)
4 + 6(x
2) (y
3)5 + (y
3)
6
R= x12
+ 6x10
y3 + 15x
8 y
6 + 20x
6 y
9 + 15x
4 y
12 + 6x
2 y
15 + y
18
4.- (3-y7)
7= ( 3)
7 + 7 (3 )
6 (-y
7) + 21( 3)
5 (-y
7)
2 + 35( 3)
4(y
7)
3+35(3)
3 ( -y
7)
4 + 21( 3)
2 ( -y
7)
5 + 7(3)
(-y 7)
6 + ( -y
7)
7
R= 2187 – 5103y14
+ 5103y14
-2835y21
+ 945y20
-189y35
21y42
–y49
7
( - )6 = (
)
6 -6 (
)5 ( ) +15 (
)4 ( )2 -20 (
)3 ( )3 +15 (
)2 ( )4 -6(
) (
)5
+( )6
=
6 -
5 +
-
+
-
+
8
(1-x4)
8 = (1)
8 - 8(1)
7(x
4) + 28(1)
6(x
4)2 -56(1)
5(x
4)3 +70 (1)
4(x
4)4 –
56(1)3(x
4)5 + 28 (1)
2(x
4)6 – 8(1)(x
4)7 + (x
4)8
= 1-8x4+28x
8-56x
12+70x
16-56x
20 + 28x
24 – 8x
28 – x
32
9. (2/3x - 3/2 y)7=
(2/3x)7 – 7(2/3x)
6(3/2y) + 21(2/3x)
5(3/2y)
2-35(2/3x)
4(3/2y)
3+35(2/3x)
3(3/2y)
4 –
21(2/3x)2(3/2y)
5+7(2/3y)
6 – (3/2y)
7=
128/2187x7 – 224/243x
6y + 56/9x
5y
2- 70/3x
4y
3 +105/2x
3y
4 – 567/8x
2y
5 + 1701/32xy
6- 2187/128y
7
R=128/2187x7 – 224/243x6y + 56/9x5y2- 70/3x4y3 +105/2x3y4 – 567/8x2y5 + 1701/32xy6-
2187/128y7
10.-
=
11.(x3+mn)
8=
(x3)
8+ 8(x
3)
7mn+ 28(x
3)
6(mn)
2 + 56 (x
3)
5(mn)
3+70 (x
3)
4(mn)
4+ 56(x
3)
3(mn)
5 + 28(x
3)
2(mn)
6+8
(x3)(mn)
7+(mn)
8=
X24
+8x21
mn+28x18
m2n
2 + 56x
15m
3n
3 + 70x
12m
4n
4+ 56x
9m
5n
5+ 28x
6m
6n
6+ 8x
3m
7n
7+m
8n
8
R= X24+8x21mn+28x18m2n2 + 56x15m3n3 + 70x12m4n4+ 56x9m5n5+ 28x6m6n6+
8x3m7n7+m8n8
12.-
=
14.
(2m₂-5m₅)₆=(2m₂)₆
(2m₂-5n₅)₆= (2m₂)₆- 6(2m₂) 5 (5n₅)+15(2m₂)₄ (5n₅)₂ -20(2m₂)₃ (5n₅)₃+15(2m₂)₂(5n₅)₄-6(2m₂)
(5n₅)₅+(5n₅)₆
=64m₁₂-960m₁₀n₅+6000m₈n₁₀-20000m₆n₁₅+37.500m₄n₃₀-37500m₂n₂+15625n₁₀
15.
(4-x5/4)₇
=(4)₇-7(4)₆(x₅/4)+21(4)₅(x₅/4)₂-35(4)₄(x₅/4)₃+35(4)3(x₅/4)₄-21(4)₂(x₅/4)₅+7(4)(x₅/4)₆-(x₅/4)₇
=16384+7168x₅+1344x₁₀-140x₁₅+35x₂₀/4-21x₂₅/64+7x₃₀/1024-1 /16384 x₃₅