CT Conduccion Ejemplos

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  • 7/26/2019 CT Conduccion Ejemplos

    1/13

    EX MPLE

    T

    he

    w

    of

    an

    i

    ndu

    s

    tr

    i

    a

    l

    fu

    rnac

    e

    is c

    onstruct

    e

    d

    fr

    om 0

    .1

    5-m-th

    i

    ck

    fire

    cl

    a

    y

    br

    i

    ck

    h

    a

    v

    i

    ng a

    t

    h

    e

    r

    m

    a

    l

    c

    o

    nd

    uc

    t

    i

    v

    i

    t

    y o

    f

    l.7

    W/

    m

    K

    .

    M

    e

    a

    s

    u

    r

    e

    m

    e

    n

    t

    s m

    a

    d

    e

    d

    ur

    i

    ng

    st

    e

    a

    d

    y-

    state

    op

    eratio

    n

    re

    ve

    a

    l

    ternperatures

    of 400 and 150 K a

    t

    th

    e

    inn

    e

    r and

    out

    er

    su

    r-

    faces

    r

    e

    sp

    e

    ctive

    ly.

    W

    hat

    is t

    he r

    a

    te o

    f

    heat

    l

    oss

    t

    hrough

    a w

    a

    l

    l that

    is

    0

    .

    5

    m

    by

    1.2

    m

    o

    n

    a

    s

    id

    e

    ?

    SOLUTIO

    N

    K

    w

    S

    t

    e

    ady-state

    c

    o

    nd

    i

    t

    i

    on

    s w

    ith

    p

    r

    esc

    ri

    b

    e

    d

    w

    a

    ll

    th

    i

    ckness ar

    e

    a

    . t

    herma

    l

    conduct

    iv

    ity

    and surface

    te

    m

    pe

    r

    a

    t

    ure

    s.

    i Wa

    ll

    heat loss.

    S

    che

    ma

    t

    ic

    :

    4

    00

    K

    1 7 W/m K

    T

    =

    1

    5

    0 K

    - - --

    L

    x

    L=

    5

    m

    Assu

    m

    pt

    o

    u

    s:

    l

    Steady-

    s

    tate

    c

    ond

    iti

    o

    ns

    2

    . One

    -

    di

    m

    e

    n

    sio

    n

    al cond

    u

    c

    t

    io

    n

    t

    h

    roug

    h

    the watt.

    3.

    Con

    stant th

    e

    rma

    l

    c

    o

    nductivity

    .

    Anu

    ys

    s

    :

    Si

    nc

    e h

    e

    at t

    ran

    sfe

    r

    throug

    h

    the wall is

    b

    y

    c

    o

    n

    d

    u

    ctio

    n

    t

    he

    h

    e

    a

    t

    flu

    x

    ma

    y

    b

    e

    de

    t

    er

    mi

    n

    ed

    fr

    om Fo

    ur i

    ers

    l

    a

    w

    .

    Usin

    g Equat

    io

    n

    .

    2

    w

    e

    h

    ave

    q

    =

    t l

    z

    =

    7

    W

    /

    m

    K

    X

    J

    :

    2

    83

    3

    W

    /

    m

    2

  • 7/26/2019 CT Conduccion Ejemplos

    2/13

    EX

    A

    M.P

    LE 1

    . 2

    A

    n

    u

    n

    i

    nsul

    a

    ted stea

    m

    pip

    e

    p

    ass

    e

    s

    t

    hr

    ou

    g

    h

    a room in

    w

    hich the air and

    wa

    l

    l

    s are

    a

    t

    2

    5

    C.

    The

    o

    u

    tsi

    de d

    i

    ame

    t

    er

    of th

    e

    p

    ipe

    i

    s

    7

    0 mm

    , and its

    s

    u

    rfac

    e

    temper

    at

    ur

    e

    and

    ern is

    sivi

    t

    y ar

    e

    200C and 0.8,

    respec

    t

    iv

    e

    l

    y

    .

    What ar

    e

    the surface

    e

    miss

    i

    ve po

    wer

    a

    nd

    i

    rr

    adi

    a

    t

    i

    o

    n

    ?

    I f

    t

    h

    e

    co

    e

    f f i

    c

    i

    e

    n

    t a

    s

    s

    o

    ci

    a

    ted

    wi

    th

    fre

    e

    c

    o

    n

    v

    e

    c

    ti

    o

    n

    h

    e

    a

    t

    t

    ran

    s

    fe

    r

    fr

    o

    m

    the surface to the air is

    15

    W

    /

    m

    2

    K , wha

    t i

    s the ra

    t

    e of

    h

    ea

    t

    l

    oss from the

    s

    u

    rfa

    ce

    per

    u

    ni

    t

    l

    eng

    t

    h o

    f

    p

    i

    pe?

    SO

    LU

    T

    IO

    N

    T10

    1

    rn:

    U

    nin

    s

    ulated

    p

    i

    pe

    o

    f

    pr

    es

    cri

    b

    ed

    di

    ameter

    ,

    emissiv

    ity, and surface tem-

    perature

    i

    n a

    ro

    om wi

    th

    fi

    x

    ed wall and

    a

    ir

    temperatures.

    Fim

    l

    :

    1.

    S

    urfac

    e

    e

    mi

    ss

    ive

    power

    a

    nd i

    rra

    d

    i

    a

    t

    ion.

    2

    .

    Pi

    p

    e

    h

    e

    at

    l

    o

    s

    s

    per

    unit

    length,

    q.

    S

    cl

    1n11al ic:

    A

    i

    r

    -

    -

    T =

    2

    00

    C

    t

    =

    0

    .

    8

    e

    T su

    ,

    =

    2

    5

    C

    L__

    T =

    2

    5

    C

    h = 15

    W /m

    2

    K

    ts

    s

    11m p

    ti

    o 11

    s:

    l. S

    te

    ad

    y

    -

    st

    ate c

    ond

    it

    ion

    s

    .

    2

    .

    R

    a

    di

    a

    ti

    o

    n

    e

    xchan

    g

    e

    b

    e

    t

    ween the

    pipe

    an

    d t

    he roo

    m

    is

    b

    etween a s

    m

    a

    ll

    su

    r

    face

    and a much

    larger

    en

    cl

    osur

    e

    .

    3.

    T

    he surface

    e

    mi

    ssiv

    i

    ty

    and

    absorpti

    vi

    ty

    are

    e

    q

    u

    al.

  • 7/26/2019 CT Conduccion Ejemplos

    3/13

    Analy

    s

    is:

    l. T

    he

    s

    u

    rf

    ace

    e

    m

    is

    s

    i

    ve

    p

    o

    w

    er

    m

    a

    y

    b

    e

    e

    va

    l

    uated from

    Equa

    t

    i

    on

    1.

    5, whil

    e

    th

    e

    i

    r

    -

    rad

    i

    a

    ti

    on

    c

    o

    r

    r

    espo

    n

    ds

    t

    o G =

    u

    T

    . Hen

    ce

    E

    =

    suT s

    4

    =

    0

    .8

    (5

    .

    67 X

    10-

    8

    W

    /

    m

    2

    K

    4

    473

    K)

    4

    =

    2270

    W

    /

    m

    2

    G

    =

    u

    Ts

    r

    = 5.67 X

    10

    -s W /m

    2

    K

    4

    (298 K)

    4

    = 4

    4

    7

    W/rn

    2

    2

    .

    H

    e

    a

    t

    l

    o

    s

    s

    from th

    e

    pipe

    is

    by

    c

    o

    nv

    ec

    ti

    o

    n to th

    e

    ro

    o

    m ai

    r

    an

    d by

    ra

    diati

    o

    n ex-

    c

    h

    a

    n

    ge

    w

    ith

    th

    e w

    a

    lls

    .

    H

    e

    n

    ce

    ,

    q = q c o

    n v

    + q r a d

    a

    n

    d from

    Equ

    a

    tion

    l

    . l O

    , with

    A

    =

    n

    D L

    ,

    q =

    h

    (

    nDL

    )

    T

    s T

    oo )

    +

    e t

    ; 7T

    D

    L

    )cr T ;

    Ts

    r)

    Th

    e

    he

    a

    t l

    oss

    per

    u

    n

    i

    t

    l

    e

    ngth

    of

    p

    i

    p

    e

    i

    s

    th

    en

    q =

    f

    = 1

    5

    W

    /

    m

    2

    Kn

    X

    0

    .

    07 m)(2

    0

    0

    -

    25

    )

    C

    +

    0.

    8

    (1r X 0.

    07

    m) 5.

    6

    7

    X

    10

    B

    W/m

    2

    K

    4

    4

    73

    4

    -

    298

    4

    K

    4

    q

    = 5

    77

    W/m +

    4

    21

    W

    /

    m

    =

    9

    98 W/m

    < J

    Co

    m

    ments:

    l.

    No

    t

    e

    t

    hat

    tem

    perature

    ma

    y

    be

    e

    x

    p

    res

    se

    d

    in u

    n

    it

    s o

    f

    C

    or K

    when

    e

    v

    alu

    a

    ting

    t

    he

    t

    emp

    e

    ra

    tur

    e

    differen

    ce

    for a c

    o

    n

    v

    ec

    t

    io

    n

    or cond

    u

    c

    t

    i

    on

    ) heat transfer ra te

    .

    H

    ow

    e

    v

    e

    r,

    temperature

    mus

    t

    b

    e

    ex

    p

    ressed

    i

    n

    kel

    v

    i

    ns

    (K) w

    h

    e

    n

    ev

    al

    uati

    ng

    a ra-

    diati

    o

    n tran

    sfer

    rate.

    2. T

    h

    e n

    e

    t ra

    t

    e

    o

    f ra

    d

    ia

    t

    i

    on

    heat t

    ra

    nsfer fro

    m

    th

    e

    pi

    pe

    ma

    y

    b

    e

    e

    x

    p

    ress

    e

    d

    as

    q ; a d = 1rD E

    aG

    )

    q c t = 1r X

    0

    .0

    7

    m 2

    270

    -

    0

    .

    8

    X

    447) W

    /

    m

    2

    =

    421 W

    /

    m

    3. I

    n

    t

    h

    i

    s

    situa

    t

    i

    on

    th

    e

    ra

    dia

    ti

    o

    n an

    d

    c

    o

    nv

    e

    cti

    o

    n h

    ea

    t t

    ra

    ns

    fe

    r ra

    t

    e

    s

    are

    c

    o

    m

    p

    arabl

    e

    be

    cause T,

    i

    s

    Jarg

    e

    c

    o

    mpared

    t

    o

    Tsu

    r

    a

    nd

    t

    he

    c

    o

    e

    f f i

    ci

    ent

    a

    ss

    o

    c

    i

    a

    te

    d w

    it

    h free

    co

    n

    -

    v

    e

    ct

    i

    on is sm

    al

    l. For more modera

    t

    e va

    l

    ues o

    f T

    s and the

    l

    a

    rger

    values o

    f

    h asso-

    ciated wi

    t

    h forced c

    o

    nvecti

    o

    n, th

    e

    effec

    t

    of radia

    ti

    o

    n

    m

    ay

    often be

    ne

    g

    l

    ec

    t

    ed.

    The

    radiati

    on h

    ea

    t

    tra

    n

    sfe

    r

    c

    o

    eff i

    c

    i

    e

    n

    t

    m

    a

    y

    b

    e

    c

    o

    mpu

    t

    ed

    f ro

    m

    Equa

    t

    ion

    1.

    9

    ,

    a

    n

    d

    for t

    h

    e

    c

    o

    nd

    iti

    o

    ns

    o

    f t

    hi

    s

    probl

    e

    m

    its val

    ue

    i

    s

    h ,.

    =

    1

    1

    W/

    m

    2

    K .

    4.

    T

    h

    i

    s

    ex

    a

    mpl

    e

    i

    s

    p

    ro

    vi

    d

    ed

    a

    s a

    t

    u

    t

    or

    i

    a

    l sessi

    on in

    t

    h

    e l

    nt

    e

    r

    a

    c

    tiv

    e

    Heat Tra

    n

    sfer

    (IHT) soft

    war

    e

    ac

    co

    m

    panying

    y

    o

    ur

    t

    ex

    t.

  • 7/26/2019 CT Conduccion Ejemplos

    4/13

    EXAMPLE 1.

    6

    Hum

    a

    n

    s

    are

    a

    b

    le

    to

    c

    ontrol

    t

    h

    ei

    r h

    ea

    t

    p

    r

    oduction

    ra

    te and h

    ea

    t Jo

    s

    s

    ra

    t

    e

    to m

    ai

    nt

    ai

    n

    a

    ne

    ar

    l

    y

    constant cor

    e

    te

    mp

    e

    ra

    tu

    re

    of

    T

    e = 37C under

    a

    wide

    ran

    g

    e

    o

    f

    envi

    r

    onmen

    -

    t

    a

    l

    co

    ndi

    t

    i

    o

    n

    s

    . Thi

    s

    pro

    c

    ess

    i

    s c

    all

    e

    d

    th

    er

    m or

    e

    g

    u

    lation

    .

    From

    the

    perspe

    c

    t

    i

    ve

    o

    f

    cal

    -

    c

    u

    l

    a

    tin

    g

    h

    ea

    t tr

    a

    n

    s

    fer b

    e

    tw

    ee

    n a hum

    a

    n

    body

    and it

    s

    su

    r

    roun

    d

    in

    g

    s,

    w

    e

    fo

    c

    us on a

    la

    y

    e

    r

    o

    f

    s

    ki

    n

    a

    nd far,

    w

    i

    t

    h i

    t

    s outer su

    rfa

    ce

    e

    xpo

    se

    d

    to the env

    i

    ronmen

    t a

    nd i

    t

    s inner

    surf

    a

    ce a

    t a

    tempera

    t

    u

    r

    e slightly

    le

    ss

    t

    ha

    n

    t

    he

    core

    temperature,

    T ;

    =

    35C

    =

    3

    08

    K

    .

    C

    on

    si

    d

    e

    ra

    person

    w

    i

    th

    a sk

    i

    n

    /

    fa

    t

    I

    ayer

    o

    f

    thickness 3 mm

    a

    nd effectiv

    e

    th

    e

    rm

    al

    condu

    c

    t

    i

    v

    i

    ty

    k = 0.3

    W

    /m K.

    T

    he

    p

    e

    rson

    ha

    s

    a surface

    are

    a A =

    1.

    8

    m

    2

    and i

    s

    d

    res

    sed i

    n a

    bathing

    suit. T

    he

    emissivi

    t

    y

    o

    f t

    h

    e

    s

    ki

    n is e =

    0

    .

    9

    5.

    l. When the

    per

    son

    is

    i

    n

    s

    till air

    a

    t T = 2

    97

    K, w

    h

    at

    i

    s th

    e

    skin

    s

    ur

    fa

    c

    e

    t

    emp

    e

    r

    a-

    tu

    r

    e

    a

    nd

    r

    ate o

    f

    heat

    l

    oss to th

    e

    environment? Convec

    t

    i

    o

    n heat t

    ra

    ns

    f

    er to the a

    i

    r

    i

    s

    ch

    a

    ra

    c

    t

    erized

    by

    a

    fre

    e

    co

    n

    v

    ec

    ti

    o

    n

    c

    o

    c

    f

    fici

    e

    n

    t

    o

    f

    h =

    2 W

    /m

    2

    K

    .

    2. Wh

    e

    n th

    e

    pe

    r

    s

    o

    o

    i

    s

    i

    n w

    a

    t

    e

    r

    at

    T

    X > =

    297 K, wh

    a

    t i

    s

    the

    s

    k

    in

    s

    u

    rf

    a

    ce

    te

    m

    pe

    r

    a

    -

    tu

    r

    e

    a

    n

    d

    heat loss

    ra

    te

    ?

    Heat t

    ra

    ns

    f

    er to the water is charact

    e

    ri

    z

    ed

    by

    a

    conv

    ec

    -

    t

    i

    o

    n c

    o

    e

    ff ici

    en

    t

    o

    f

    h

    =200 W

    /m

    2

    K

    SOLUTIO

    N

    K 11own:

    In

    ne

    r

    su

    rfa

    ce

    te

    mp

    e

    r

    a

    tu

    re

    o

    f a

    skin/fat la

    y

    e

    r

    o

    f

    kn

    o

    wn thickn

    e

    ss

    ,

    the

    r

    -

    m

    al

    c

    ondu

    c

    tivity,

    e

    missivity,

    and

    s

    urface ar

    ea

    . Ambi

    e

    nt

    c

    ond

    iti

    ons.

    Fiu

    d : Skin

    su

    rfa

    ce

    t

    emp

    e

    ratur

    e

    a

    n

    d

    heat l

    os

    s rat

    e for

    the

    person

    in

    a

    i

    r a

    nd the

    p

    e

    r

    s

    o

    n

    in

    w

    a

    t

    e

    r

    .

    Schem

    a

    tici

    1

    1

    =308

    K

    k

    =

    0

    .

    3

    W

    /

    m

    K

    T

    11

    s

    E= 0.

    9

    5

    1

    1

    ___...q ;

    1

    q

    ______.,.

    1

    c o n