Aporte Desarrollo Punto 3 Algebra Lineal
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3 x−4 y−7 z=−11 5 x−7 y−2 z=−9 −4 x−y−6 z=7 A= [ 3 −4 −7 5 −7 −2 −4 −1 −6 ] [ 3 −4 −7 5 −7 −2 −4 −1 −6 ] 3 − 4 5 −7 −4 −1 ¿ ( 3. −7.−6 ) +( −4.2. −4) +(−7 . 5.−1) ¿ −(−4. −7.−7 )− (−1.− 2.3 )− (−6.5.−4 ) [ A ]=126−16 −36 + 196+ 6+120 [ A ]=39 6 A 11 =+ [ −7 −2 −1 −6 ] =40 A 12 =− [ −4 −2 −7 −6 ] =10 A 13 =+ [ 5 −7 −4 −1 ] =¿ A 21 =− [ −4 −7 −1 −6 ] =22 A 22 =+ [ 3 −7 −6 −4 ] =−54 A 23 =− [ 3 −4 −4 −1 ] A 31 =+ [ −4 −7 −7 −2 ] =41 A 32 =− [ 3 −7 5 −2 ] =29 A 33 =+ [ 3 −4 5 −7 ] A dA = [ 40 10 −33 22 −54 −28 41 29 −1 ]
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Alegra lineal - UNAD
Transcript of Aporte Desarrollo Punto 3 Algebra Lineal
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