Algoritmo Despues Del Parcial Metodos.

7/23/2019 Algoritmo Despues Del Parcial Metodos.

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metodo de euler

conclusion=nose deriva nada de nada como si el c

tambien=mientras mas pequeño sea h se mejora mas la aproxim

algoritmos solo poner 4 datos x0,y(x0),y"(ngresar datos

valor de la !uncion en# h= 0$0%

xo 0

y(xo) & estan son las

y'(xo) &

diere en cada problema

n n *n *'n h*'n *n+&

0 0 & & 0$0% &$0%

& 0$0% &$0% &$004 0$0%&%0- &$04&%0-

% 0$04 &$04&%0- &$&%%-./% 0$0%%4.&/ &$0/.&// 0$0 &$0/.&%4 &$&-4-.0/4 0$0%/41 &$0-4&4-/

4 0$0- &$0-4&4-%& &$%.440-0&/% 0$0%.0--& &$&&%.0%11

. 0$& &$&&%.0%1-/ &$/%/./%-& 0$0%4.0 &$&/-1-0.

0$&% &$&/-1-0./& &$/1...4&14 0$0%1&/&& &$&-1&&

0$&4 &$&-1&&&. &$40%..1%4& 0$0%140.&% &$&1%1%-

- 0$& &$&1%1%11 &$.40/-4 0$0/01.40 &$%%%.0/.

1 0$&- &$%%%.0/./ &$%-&..4&/ 0$0/%./&& &$%.1-&/4

&0 0$% &$%.1-&/4% &$&&&.44 0$0/4%/..% &$%1404-11

&& 0$%% &$%1404-1-.& &$1-/1&- 0$0/.14- &$//00%/-

&% 0$%4 &$//00%/-0/ &$--1%%14- 0$0/-4.1 &$/-0-/&/ 0$% &$/-0-/0& &$1-/4/-.4/ 0$0/1- &$404&4

&4 0$%- &$404&4& %$0-&.0404 0$04&/&4& &$441&0-.

el metodo consiste en encon



&. 0$/ &$441&0-...- %$&-/-4&&%%. 0$04/-% &$41%-./-

& 0$/% &$41%-./-% %$%10411/ 0$04.-01./ &$./-.141&

& 0$/4 &$./-.141&%% %$40&&&-%4 0$04-0/4/4 &$.-%1%

&- 0$/ &$.-%1%..1 %$.&-&.-- 0$0.0/./% &$/1-..

&1 0$/- &$/1-..& %$/10400--- 0$0.%-0- &$-1/

%0 0$4 &$-1//4 %$.%1%%- 0$0../&/4 &$4.01-/

%& 0$4% &$4.01-/&1 %$-1-0&//&% 0$0.10% &$-0/040&%% 0$44 &$-0/040011& /$0//4% 0$00%.. &$-/.

%/ 0$4 &$-/./1 /$&-&&004- 0$0/%%0% &$1%/-1

%4 0$4- &$1%/-114 /$//%./&0- 0$0.0/ &$1140404

%. 0$. &$11404040/ /$41&000.. 0$01-%&%& %$0/-&%

% 0$.% %$0/-&&.- /$.01. 0$0/&4&/1 %$&/00/0&

% 0$.4 %$&/00/00-1 /$-/01-4// 0$0&11 %$%&/%%



so de taylor

cion

0),h

respuestas(yn)

2 0$.

i Xi Yi

0 1 0.51 1 #DIV/0!

2 1 #DIV/0!

trar el nuevo "y" por metodo de tangente ala curva

0$./

0$.4

0$..

0$.



3 1 #DIV/0!

4 1 #DIV/0!

5 1 #DIV/0!

0$.

0$4

0$4-

0$41

0$.

0$.&

$



& &$. % %$. / /$.

3olumn



metodo de taylor(4) solo poner % datos datos de amarillo y

poner ese dato

poner todas esta derivadas

ngresar atosh 0$0% 5(x) en 0$&

xo 0 0 0 0

y(0) & & & &

y'(0) & & & &

y''(0) / / / /

y'''(0) . . . .

y''''(0) &4 &4 &4 &4

h 0$0% 0$0% 0$0% 0$0%x 0 0$0% 0$04 0$0

y & &$0%00 &$04%4.4-/ &$0..-.

tabla deresultados



sus derivada

0 0 0 0 0 0

& & & & & &

& & & & & &

/ / / / / /

. . . . . .

&4 &4 &4 &4 &4 &4

0$0% 0$0% 0$0% 0$0% 0$0% 0$0%0$0- 0$& 0$&% 0$&4 0$& 0$&-

&$0100.0. &$&&.-1& &$&4/&01 &$&&1&0 &$%0%&1./ &$%/40%/

conclusion=solo trabajaremosen las derivadas y nada mas yya salio



0 0 0 0

& & & &

& & & &

/ / / /

. . . .

&4 &4 &4 &4

0$0% 0$0% 0$0% 0$0%0$% 0$%% 0$%4 0$%

&$% &$/0%-/1-/ &$//1-../ &$/-&%/



metodo de runger 6utta(4) tampoco se deriva s

algoritmongresar datos

valor de la !uncion en# estos / datos van y lxo 0

y(xo) &

poner ecuacion aqui

h 0$0% cada !uncion tiene di!er

n n *n *'n 9& n + 0$.h

0 0 & & 0$0% 0$0&

& 0$0% &$0%00 &$0&0&-1 0$0%&%%0/- 0$0/

% 0$04 &$04%4.4- &$&%4&./0. 0$0%%4-/0 0$0.

/ 0$0 &$0..-1 &$&-1.%/0. 0$0%/104 0$0

4 0$0- &$0100.&./ &$%.%... 0$0%.&4.&& 0$01

. 0$& &$&&.-14. &$/%4-4&% 0$0%.41- 0$&&

0$&% &$&4/&-4 &$400/4-- 0$0%-001 0$&/

esta son lasrepuestas parcada xn



0$&4 &$&&1%&. &$4.111 0$0%1.&114 0$&.

- 0$& &$%0%%%1/ &$..4.-44 0$0/&01&1 0$&

1 0$&- &$%/4&/&%& &$/%4-/ 0$0/%%.. 0$&1

&0 0$% &$%00 &$%&%401% 0$0/44%4-% 0$%&

&& 0$%% &$/0/00/1 &$-014 0$0/&1// 0$%/

&% 0$%4 &$/40&&&- &$10&/-41 0$0/-0/4 0$%.

&/ 0$% &$/1011&% &$114-1 0$0/11.// 0$%&4 0$%- &$4%004./1 %$01.-& 0$04&1./& 0$%1

&. 0$/ &$4/0/40 %$%0&144%- 0$0440/--1 0$/&

& 0$/% &$.0-&.// %$/&0%4. 0$04%&.%. 0$//

& 0$/4 &$...414. %$4%4/.%. 0$04-4-/ 0$/.

&- 0$/ &$0.&&. %$.4/0&1-. 0$0.0-04 0$/

&1 0$/- &$.%.%-& %$00-- 0$0.//40&- 0$/1

%0 0$4 &$&&-1. %$1/&/1 0$0..1/%/ 0$4&



lo se rempla7a valores a di!erncia de taylor que si se deriva

s !unciones 8echa cambiar solo la !uncion n

te regla correspondencia

*n + 0$.9& 9% *n + 0$.9% 9/ *n+9/ n + h

&$0& 0$0%00% &$0&0/0& 0$0%00-0- &$0%00-0- 0$0%

&$0/&%&1. 0$0%&-4/0 &$0/&.%-/ 0$0%&-414- &$04%4.%4 0$04

&$0./1/1 0$0%/&%% &$0.40&- 0$0%/&/4/1 &$0..-1%. 0$0

&$04-/0% 0$0%44.-&4 &$0-&- 0$0%44.%- &$0100./0 0$0-

&$&0%%40- 0$0%.-/%& &$&0%10&/ 0$0%.-44. &$&&.-1%- 0$&

&$&%1&141 0$0%%. &$&%1.%-4/ 0$0%%../ &$&4/&0&- 0$&%

&$&.&&1. 0$0%-.%01 &$&..44.& 0$0%-0.& &$&&1%-1 0$&4



&$&--&% 0$0/0%1/- &$&-040 0$0/0/0% &$%0%%%1- 0$&

&$%&/- 0$0/&-1.1& &$%&-&.-1 0$0/&10./% &$%/4&//%. 0$&-

&$%.041/1 0$0//.& &$%.01&%01 0$0//.&& &$%0%1% 0$%

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&$/%&&00.. 0$0/0110 &$/%&../44 0$0/&&0%& &$/40&&4&& 0$%4

&$/.1&%10 0$0/-1-%/ &$/.100- 0$0/-1100% &$/1&0& 0$%

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&$4-.0./. 0$04.&0-4 &$4-..--% 0$04.&%%4& &$.0-&.4 0$/%

&$./&%011 0$04//&.4 &$./&-&1&4 0$04/4/1 &$...411 0$/4

&$.140&& 0$041.%1- &$.-0/%%1. 0$041-% &$0.&.& 0$/

&$/0.1&-. 0$0.%0-%% &$/&%00 0$0.%0141 &$.%.. 0$/-

&$-/1%%1 0$0.4&/0 &$-4..1// 0$0.4/0. &$&&--/. 0$4

&$/1-4.-- 0$0.%/. &$40.&&/1 0$0.%-%4% &$1&&1- 0$4%



o el h$

94 *n+& h

0$0%&%%04 &$0%00 0$0%

0$0%%4-/01 &$04%4.4- 0$0%

0$0%/1041 &$0..-1 0$0%

0$0%.&4.&. &$0100.&./ 0$0%

0$0%.41% &$&&.-14. 0$0%

0$0%-000& &$&4/&-4 0$0%

0$0%1.&11- &$&&1%&. 0$0%



0$0/&01&/ &$%0%%%1/ 0$0%

0$0/%%..4 &$%/4&/&%& 0$0%

0$0/44%4- &$%00 0$0%

0$0/&1//. &$/0/00/1 0$0%

0$0/-0/4-/ &$/40&&&- 0$0%

0$0/11.// &$/1011&% 0$0%

0$04&1./%/ &$4%004./1 0$0%0$0440/-1 &$4/0/40 0$0%

0$04%&.// &$.0-&.// 0$0%

0$04-4-/1 &$...414. 0$0%

0$0.0-041 &$0.&&. 0$0%

0$0.//40%- &$.%.%-& 0$0%

0$0..1/%4 &$&&-1. 0$0%

0$0.-44% &$1&.% 0$0%



metodo de gauss:seidel(%)

coecientes a b c nota#

ecuacion & / :& :&

ecuacion% :& / &

por lo general son ceros

6 x& x% x&(nal) x%(nal)

0 :0$//////// 0$%%%%%%%%

& :0$//////// 0$%%%%%%%% :0$%.1%.1% 0$%41&/.-

% :0$%.1%.1% 0$%41&/.- :0$%.&0%--& 0$%41.0

/ :0$%.&0%--& 0$%41.0 :0$%.0&&4/& 0$%411&1

4 :0$%.0&&4/& 0$%411&1 :0$%.00&% 0$%4111.

. :0$%.00&% 0$%4111. :0$%.000&4& 0$%41111./

:0$%.000&4& 0$%41111./ :0$%.0000& 0$%411111.

:0$%.0000& 0$%411111. :0$%.00000% 0$%4111111

- :0$%.00000% 0$%4111111 :0$%. 0$%.

1 :0$%. 0$%. :0$%. 0$%.

&0 :0$%. 0$%. :0$%. 0$%.

&& :0$%. 0$%. :0$%. 0$%.

&% :0$%. 0$%. :0$%. 0$%.

&/ :0$%. 0$%. :0$%. 0$%.

&4 :0$%. 0$%. :0$%. 0$%.&. :0$%. 0$%. :0$%. 0$%.

& :0$%. 0$%. :0$%. 0$%.

& :0$%. 0$%. :0$%. 0$%.



son di!erntes de cero mi algoritmo no permite esto division entre c



ro



metodo de gauss:deidel(/)

coecientes a b c d

ecuacion & / :& :& &

ecuacion% :& / & /

ecuacion / % & 4

asumiendo por lo general

6 x& x% x/ x&(nal) x%(nal)

0 0 0 0 0$//////// &$&&&&&&&&& 0$//////// &$&&&&&&&& &$/0..... &$&/-----1 0$14444444

% &$&/-----1 0$14444444 0$14444444 0$1%1%1 &$00&%-4

/ 0$1%1%1 &$00&%-4 &$0&1./& &$00&0. 0$111&/.-

4 &$00&0. 0$111&/.- 0$111&/.- 0$1114%/1 &$000/4%14

. 0$1114%/1 &$000/4%14 &$00014/0 &$0004%- 0$111-%-./

&$0004%- 0$111-%-./ 0$111-%-./ 0$111--.1 &$0000&10.

0$111--.1 &$0000&10. &$0000.%/1 &$0000%/-& 0$1111104

- &$0000%/-& 0$1111104 0$1111104 0$11111/. &$00000&0

1 0$11111/. &$00000&0 &$00000%1& &$00000&/% 0$1111114

&0 &$00000&/% 0$1111114 0$1111114 0$111111. &$0000000&& 0$111111. &$0000000 &$000000& &$0000000 0$1111111

&% &$0000000 0$1111111 0$1111111 0$1111111- &

&/ 0$1111111- & &$0000000& & &

&4 & & & & &

&. & & & & &

& & & & & &

& & & & & &



nota# es di!erente de cero mi algoritmo no lo permite(divis

on ceros

x/(anl)

&$/0.....0$14444444

&$0&1./&

0$111&/.-

&$00014/0

0$111-%-./

&$0000.%/1

0$1111104

&$00000%1&

0$1111114

&$000000&0$1111111

&$0000000&

&

&

&

&

&



n entre cero)



metodo de gauss:seidel

orden(4)coecientes a b c d e

ecuacion & % 0 & & 4

ecuacion% & 4 0 :& 4

ecuacion / & 0 % & 4

ecuacion 4 & 0 & % 4


6 x& x% x/ x4 x&(nal)

0 0 0 0 0 %

& % 0$. & 0$. &$%.

% &$%. 0$-&%. &$&%. 0$-&%. &$0/&%.

/ &$0/&%. 0$14./&%. &$0-&%. 0$14./&%. 0$1--%-&%.

4 0$1--%-&%. 0$1-1%.-& &$0//%0/&/ 0$1-1%.-& 0$1--1./

. 0$1--1./ &$000&%%0 &$0&01-// &$000&%%0 0$11444.-

0$11444.- &$00&4&10 &$00%&0 &$00&4&10 0$111/%4/

0$111/%4/ &$000-& &$000/%4%. &$000-& 0$11140%0.

- 0$11140%0. &$000/4 0$111-/&. &$000/4 0$111--4%1 0$111--4% &$000&%0 0$111-/14 &$000&%0 &$00000%

&0 &$00000% &$0000%141 0$1111/-/% &$0000%141 &$0000&&

&& &$0000&& &$00000//. 0$1111%& &$00000//. &$000001%

&% &$000001% 0$11111-4& 0$11111/4 0$11111-4& &$0000040

&/ &$0000040 0$11111-.1 0$11111- 0$11111-.1 &$00000&//

&4 &$00000&// 0$111111/% &$00000004 0$111111/% &$000000/%

&. &$000000/% 0$111111. &$000000&- 0$111111. &$0000000/

& &$0000000/ 0$1111111/ &$000000&& 0$1111111/ 0$1111111-

& 0$1111111- 0$11111111 &$00000004 0$11111111 0$1111111-



nota# son di!erentes de cero(sino estaria divid

on ceros

x%(nal) x/(nal) x4(nal)

0$. & 0$.

0$-&%. &$&%. 0$-&%.

0$14./&%. &$0-&%. 0$14./&%.

0$1-1%.-& &$0//%0/&/ 0$1-1%.-&

&$000&%%0 &$0&01-// &$000&%%0

&$00&4&10 &$00%&0 &$00&4&10

&$000-& &$000/%4%. &$000-&

&$000/4 0$111-/&. &$000/4

&$000&%0 0$111-/14 &$000&%0&$0000%141 0$1111/-/% &$0000%141

&$00000//. 0$1111%& &$00000//.

0$11111-4& 0$11111/4 0$11111-4&

0$11111-.1 0$11111- 0$11111-.1

0$111111/% &$00000004 0$111111/%

0$111111. &$000000&- 0$111111.

0$1111111/ &$000000&& 0$1111111/

0$11111111 &$00000004 0$11111111

& &$0000000& &



ido entre cero)y no esta contenplado en mi algoritmo



metodo de jacobi(%)

coecientes a b c notaecuacion & / :& :&

ecuacion% :& / &

por lo general son ceros

6 x& x% x&(nal) x%(nal)

0 0 0 :0$//////// 0$////////

& :0$//////// 0$//////// :0$%%%%%%%% 0$%%%%%%%%

% :0$%%%%%%%% 0$%%%%%%%% :0$%.1%.1% 0$%.1%.1%

/ :0$%.1%.1% 0$%.1%.1% :0$%41&/.- 0$%41&/.-

4 :0$%41&/.- 0$%41&/.- :0$%.&0%--& 0$%.&0%--&

. :0$%.&0%--& 0$%.&0%--& :0$%41.0 0$%41.0

:0$%41.0 0$%41.0 :0$%.0&&4/& 0$%.0&&4/&

:0$%.0&&4/& 0$%.0&&4/& :0$%411&1 0$%411&1

- :0$%411&1 0$%411&1 :0$%.00&% 0$%.00&%

1 :0$%.00&% 0$%.00&% :0$%4111. 0$%4111.

&0 :0$%4111. 0$%4111. :0$%.000&4& 0$%.000&4&

&& :0$%.000&4& 0$%.000&4& :0$%41111./ 0$%41111./

&% :0$%41111./ 0$%41111./ :0$%.0000& 0$%.0000&

&/ :0$%.0000& 0$%.0000& :0$%411111. 0$%411111.

&4 :0$%411111. 0$%411111. :0$%.00000% 0$%.00000%

&. :0$%.00000% 0$%.00000% :0$%4111111 0$%4111111

& :0$%4111111 0$%4111111 :0$%. 0$%.

& :0$%. 0$%. :0$%. 0$%.

&- :0$%. 0$%. :0$%. 0$%.

&1 :0$%. 0$%. :0$%. 0$%.

%0 :0$%. 0$%. :0$%. 0$%.

%& :0$%. 0$%. :0$%. 0$%.

%% :0$%. 0$%. :0$%. 0$%.

%/ :0$%. 0$%. :0$%. 0$%.

%4 :0$%. 0$%. :0$%. 0$%.%. :0$%. 0$%. :0$%. 0$%.

% :0$%. 0$%. :0$%. 0$%.

% :0$%. 0$%. :0$%. 0$%.



nunca deben ser ceros mi algoritmo no contenpla division entre se



o



metodo de jacobi(/)

coecientes a b c d

ecuacion & / :& :& &

ecuacion% :& / & /

ecuacion / % & 4


6 x& x% x/ x&(nal) x%(nal)

0 0 0 0 0$//////// && 0$//////// & &$. &$%. 0$.%-

% &$%. 0$.%- &$//////// 0$1./0/ 0$1%%%%%%

/ 0$1./0/ 0$1%%%%%% 0$11/0... 0$1--4%.1/ 0$1---%%

4 0$1--4%.1/ 0$1---%% &$0/001%.1 &$00..-44 0$1-&&&&&

. &$00..-44 0$1-&&&&& &$0010/ 0$11-/1%41 0$11--40/

0$11-/1%41 0$11--40/ &$0004/ 0$111-/.- 0$111%41-/

0$111-/.- 0$111%41-/ &$00&0-. &$000&&%./ 0$111.-%4

- &$000&&%./ 0$111.-%4 &$000%1 0$1111.0- 0$11114&

1 0$1111.0- 0$11114& &$00004-0- 0$11111-. 0$1111.

&0 0$11111-. 0$1111. &$0000/& &$00000& 0$1111-1.&& &$00000& 0$1111-1. &$00000--/ 0$11111-.1 0$111114

&% 0$11111-.1 0$111114 &$00000%/- &$0000000& 0$11111-4

&/ &$0000000& 0$11111-4 &$00000&%1 &$0000000& 0$111111.

&4 &$0000000& 0$111111. &$000000/& 0$1111111 0$1111111

&. 0$1111111 0$1111111 &$000000& & 0$1111111.

& & 0$1111111. &$00000004 & 0$11111111

& & 0$11111111 &$0000000& & &

&- & & & & &

&1 & & & & &

%0 & & & & &

%& & & & & &

%% & & & & &

%/ & & & & &

%4 & & & & &

%. & & & & &

% & & & & &

% & & & & &

%- & & & & &



nota# nunca deben ser ceros mi algoritmo no conplenpla es

on ceros

x/(anl)

&$.&$////////

0$11/0...

&$0/001%.1

&$0010/

&$0004/

&$00&0-.

&$000%1

&$00004-0-

&$0000/&

&$00000--/&$00000%/-

&$00000&%1

&$000000/&

&$000000&

&$00000004

&$0000000&

&

&

&

&

&

&

&

&

&

&

&

&



to



metodo de jacobi(4)

coecientes a b c d eecuacion & &0 :& % 0

ecuacion% :& && :& / %.

ecuacion / % :& &0 :& :&&

ecuacion 4 0 / :& - &.


6 x& x% x/ x4 x&(nal)

0 0 0 0 0 0$

& 0$ %$%%%% :&$& &$-. &$04%%/

% &$04%%/ &$&.10101 :0$-0.%%% 0$--.%%% 0$1/%//

/ 0$1/%// %$0.//0.1 :&$041/401& &$&/0--0- &$0&.&1-

4 &$0&.&1- &$1./1. :0$1-&0-/ 0$1/-4%% 0$1--11&/

. 0$1--11&/ %$0&&4&4/ :&$0&0%-.1 &$0%&/.0.& &$00/&1-.

&$00/&1-. &$11%%4&% :0$114.%&4 0$1144//4 0$11-&%-4

0$11-&%-4 %$00%/0-- :&$00&1%%/ &$00/.14/& &$000%.&/

- &$000%.&/ &$11-0/ :0$1110/..- 0$11----/1 0$1114&.

1 0$1114&. %$00044 :&$000/1& &$000&1&1 &$000&&-

&0 &$000&&- &$1111. :0$111-%-&4 0$111-.1- 0$11114%4%

&& 0$11114%4% %$0000-4 :&$0000-// &$000&0-. &$0000%%&4

&% &$0000%%&4 &$1111.-1 :0$11111& 0$1111.1 0$1111-1/

&/ 0$1111-1/ %$0000&.-% :&$0000&%. 0$111111% &$00000401

&4 &$00000401 &$11111-41 :0$11111. 0$111111 0$111111&

&. 0$111111& %$0000001 :&$00000&0 &$0000000 &$000000/&

& &$000000/& &$111111-& :0$111111/ 0$11111114 0$1111111/

& 0$1111111/ %$0000000 :&$00000001 &$000000&& &$0000000%

&- &$0000000% &$1111111 :& 0$1111111 0$11111111

&1 0$11111111 %$0000000% :& &$0000000% &

%0 & &$11111111 :& 0$11111111 &

%& & % :& & &

%% & % :& & &%/ & % :& & &

%4 & % :& & &

%. & % :& & &

% & % :& & &

% & % :& & &



nota# di!erente de cero en mi algoritmo no est

on ceros

x%(nal) x/(nal) x4(nal)

%$%%%% :&$& &$-.

&$&.10101 :0$-0.%%% 0$--.%%%

%$0.//0.1 :&$041/401& &$&/0--0-

&$1./1. :0$1-&0-/ 0$1/-4%%

%$0&&4&4/ :&$0&0%-.1 &$0%&/.0.&

&$11%%4&% :0$114.%&4 0$1144//4

%$00%/0-- :&$00&1%%/ &$00/.14/&

&$11-0/ :0$1110/..- 0$11----/1

%$00044 :&$000/1& &$000&1&1

&$1111. :0$111-%-&4 0$111-.1-

%$0000-4 :&$0000-// &$000&0-.

&$1111.-1 :0$11111& 0$1111.1

%$0000&.-% :&$0000&%. 0$111111%

&$11111-41 :0$11111. 0$111111

%$0000001 :&$00000&0 &$0000000

&$111111-& :0$111111/ 0$11111114

%$0000000 :&$00000001 &$000000&&

&$1111111 :& 0$1111111

%$0000000% :& &$0000000%

&$11111111 :& 0$11111111

% :& &

% :& &

% :& &% :& &

% :& &

% :& &

% :& &

% :& &



a contenplado divison entre 0



metodo de cholesc6y(%) solo son para m

coecientes a b c

ecuacion & % & /ecuacion% & % /

matri7 ;

;&& ;%& ;%%

<;>?@A &$4&4%&/. 0$0&0- &$%%444-

2>? calculamos vector " y", ;B*=C

coecientes a b C

ecuacion & &$4&4%&/. 0 /

ecuacion% 0$0&0- &$%%444- /

DE?F " y" es

valores

y& %$&%&/%0/4

y% &$%%444-

2>? calculamos vector " x", ;GtBx=y

valores

x& &

x% &



trices simetricas



metodo de choles6y(/)solo son para matrices simetricas

coecientes a b c d

ecuacion & 4 & % &

ecuacion% & % 0 %

ecuacion / % 0 . 4

matri7 ; luego de estas operaciones

;&& ;%& ;/& ;%% ;/%

<;>?@A % 0$. & &$/%%-. :0$/144


coecientes a b c C

ecuacion & % 0 0 &

ecuacion% 0$. &$/%%-. 0 %

ecuacion / & :0$/144 &$1/1&0& 4

DE?F " y" es

valores

y& 0$.

y% &$/%%-.

y/ %$0/00/&

2>? calculamos vector " x", ;GtBx

valores

x& :0$.1%.1%.1

x% &$%1%1/

x/ &$0/0/04

B

B



;//

&$1/1&0&

=

y

=



metodo de cholesc6y(4) solo son para mat

coecientes a b c d eecuacion & 4 :& 0 %

ecuacion% :& 4 :& 0 /

ecuacion / 0 :& 4 & &

ecuacion 4 % 0 & / &%

matri7 ;

;&& ;%& ;/& ;4& ;%%

valores % :0$. 0 & &$1/41&


coecientes a b c d C

ecuacion & % 0 0 0

ecuacion% :0$. &$1/41& 0 0 /

ecuacion / 0 :0$.&/1- &$1/%&-/. 0 &

ecuacion 4 & 0$%.-&1--1 0$.-.../ &$%0- &%

DE?F " y" es

valores

y& /

y% %$/%/100&

y/ -$10&-4.%

y4 %$.%&//.&

2>? calculamos vector " x", ;GtBx=y

valores

x& &



x% %

x/ 4

x4 %



ices simetricas

;/% ;4% ;// ;4/ ;44

:0$.&/1- 0$%.-&1--1 &$1/%&-/. 0$.-.../ &$%0-

B =



B =



metodo de potencia(%)

& &

& :& solo pone

<= & &

H

B<= % 0

G%B<= % % & G

G/B<= 4 0 %

G4B<= 4 4 &

G.B<= - 0 %

GB<= - - & G4= GB<= & 0 %

G=



estas % matrices la maquina trabaja sola

% 0 G/= % %

0 % % :%

4 0 G. 4 40 4 4 :4

- 0 G= - -

0 - - :-



metodo de potencia orden (/)

& 0 %

0 & / solo esta % m

& & &

< 0$-144 &$/4& &

H G%

B<= %$-144 4$/4& /$%/

G%B<= 1$/4 &4$041 &0$4% /$%/04%0&

G/B<= /0$/&04 4.$4. //$--- /$%/01

G4B<= 1-$0-4 &4$&%1 &01$4 /$%/04&1 G4

G.B<= /&$4&44 4$&%& /.4$-- /$%/014%

GB<= &0%$&44 &.40$& &&4-$4& /$%/04% GB<= //%4$004 41-$001 /&$/.% /$%/0-&1

G=



atrices poner los datos y ya la maquiina trabaja solo

/ % 4

/ 4 G/= 1 &0

% % - -

%/ %% 4- & 0

// /4 % G.= &0. &0

%4 %4 . -0 -0

%/& %/0 .&% 4/ 4%

/4. /4 - G= &&&/ &&&4

%. %. . -/% -/%



&

%4

&

&0

%40

&

&4

%41

&-.

Algoritmo Despues Del Parcial Metodos.

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Transcript of Algoritmo Despues Del Parcial Metodos.