ALGEBRA LINEAL RELACION 3
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FORMA CANONICA DE JORDAN 1. Calcular la forma can´onica de Jordan y la matriz de paso para las siguientes matrices: (a) A = 0 1 -1 0 0 -1 0 1 1 1 0 0 0 -2 0 1 (b) A = 6 -9 5 4 7 -13 8 7 8 -17 11 8 1 -2 1 3 (c) A = 3 1 -1 1 0 2 0 1 1 1 1 0 0 0 0 2 (d) A = 2 0 0 -2 5 2 -2 2 3 1 0 -3 1 0 0 0 (e) A = -1 2 -3 0 1 -1 1 -1 2 (f) A = -1 3 -5 2 0 0 1 -3 1 0 0 1 -2 0 0 0 0 1 -2 0 0 -1 3 -2 -1 1
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PROBLEMAS FORMA CANONICA DE JORDAN
Transcript of ALGEBRA LINEAL RELACION 3
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FORMA CANONICA DE JORDAN
1. Calcular la forma canonica de Jordan y la matriz depaso para las siguientes matrices:
(a) A =
0 1 1 00 1 0 11 1 0 00 2 0 1
(b) A =
6 9 5 47 13 8 78 17 11 81 2 1 3
(c) A =
3 1 1 10 2 0 11 1 1 00 0 0 2
(d) A =
2 0 0 25 2 2 23 1 0 31 0 0 0
(e) A =
1 2 30 1 11 1 2
(f) A =
1 3 5 2 00 1 3 1 00 1 2 0 00 0 1 2 00 1 3 2 1
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(g) A =
6 0 0 30 6 0 00 3 6 00 0 0 6
(h) A =
2 1 1 22 1 1 01 0 0 11 2 0 1
(i) A =
3 1 0 19 5 0 93 2 1 34 3 0 6
(j) A =
0 1 1 1 12 3 1 1 12 1 3 1 13 3 0 3 16 9 6 7 5
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