Sujeto Item Item Item Item Item Item Item Item Item Item Item Item1 2 3 4 5 6 7 8 9 10 11 12 Total (X) ∑X2

1 4 4 3 2 1 1 2 3 4 5 1 2 32 10242 3 1 3 3 1 2 3 4 5 1 2 3 31 9613 4 5 4 4 4 4 3 5 4 2 3 1 43 18494 4 3 2 3 1 1 4 5 3 2 1 2 31 9615 5 2 4 4 3 1 3 4 5 1 2 3 37 13696 5 4 3 2 4 2 2 4 3 1 2 3 35 12257 4 4 2 3 2 3 4 3 2 1 5 3 36 12968 4 4 2 5 2 4 4 3 5 2 1 3 39 15219 4 4 3 3 2 4 3 4 2 5 3 1 38 1444

10 5 4 4 4 4 4 3 4 4 5 1 3 45 2025Total 43 37 33 37 29 32 38 47 46 35 32 36 367 13675

∑X2 180 135 96 117 72 84 101 157 149 91 59 640.4 1.38 0.66 0.9 1.6 1.82 0.54 0.54 1.34 3.16 1.65 0.91Vi2

Calculo de la varianza

∑X2 – (∑X) VF= n______

n-1

13675 – ( 367)2 10 Vf = _____________________ = 23 10-1 Calculo de la varianza individual

∑X2 – (∑X) VF= n______

n-1 180- ( 42)2 10 V1 = _________________ = 0,4 10-1 135- ( 35)2 10 V2 = _________________ = 1,38 10-1 96- ( 30)2 10 V3 = _________________ = 0,66 10-1 117- ( 33)2 10 V4 = _________________ = 0,9 10-1

72- ( 24)2 10 V5 = _________________ = 1,6 10-1 84- ( 26)2 10 V6 = _________________ = 1,82 10-1 101- ( 31)2 10 V7 = _________________ = 0,54 10-1 157- ( 39)2 10 V8 = _________________ = 0,54 10-1

149- ( 37)2 10 V9 = _________________ = 1,34 10-1 91- ( 25)2 10 V10 = _________________ = 3,16 10-1

59- ( 21)2 10 V11 = _________________ = 1,65 10-1 641- ( 24)2 10 V12 = _________________ = 0,91 10-1

Calculo del coeficiente de confiabilidad formula alfa de cronbach (n) * (1- ∑Vi) Rt = n-1 vt Rt = (12) * ( 1-15) = -0,66 12-1 23

149- ( 37)2 10 V9 = _________________ = 1,34 10-1 91- ( 25)2 10 V10 = _________________ = 3,16 10-1

59- ( 21)2 10 V11 = _________________ = 1,65 10-1 641- ( 24)2 10 V12 = _________________ = 0,91 10-1

Calculo del coeficiente de confiabilidad formula alfa de cronbach (n) * (1- ∑Vi) Rt = n-1 vt Rt = (12) * ( 1-15) = -0,66 12-1 23

Sujeto Item Item Item Item Item Item Item Item Item Item Item Item1 2 3 4 5 6 7 8 9 10 11 12 Total (X) ∑X2

1 1 1 1 1 1 0 0 1 1 1 1 1 10 1002 0 1 1 1 1 1 1 1 1 0 0 1 9 813 1 0 0 0 0 0 1 0 0 1 1 0 4 164 1 1 1 1 1 1 0 1 1 1 1 1 11 1215 0 0 0 0 1 1 1 1 1 1 1 1 8 646 1 1 1 1 0 0 0 0 0 0 0 1 5 257 1 1 0 0 1 1 1 1 1 1 1 1 10 1008 1 0 0 0 1 1 1 0 1 1 1 1 8 649 0 1 1 1 0 0 0 1 0 0 0 0 4 16

10 0 0 0 0 0 0 1 0 0 0 0 1 69 4Total de frecuencia 6 6 5 5 6 5 6 6 6 6 6 8 591P 0.6 0.6 0.5 0.5 0.6 0.5 0.6 0.6 0.6 0.6 0.6 0.8q 0.4 0.4 0.5 0.5 0.4 0.5 0.4 0.4 0.4 0.4 0.4 0.2p*q 0.24 0.24 0.25 0.25 0.24 0.25 0.24 0.24 0.24 0.24 0.24 0.16 2.83

Calculo de la varianza

∑(X – Ẋ)2

VF= ______ n-1

591 – ( 63)2 Vf = _____________________ = 21,56 10-1

Calculo del coeficiente de confiabilidad formula alfa de KR20 (n) * (1- ∑p.q) Rt = n-1 vt Rt = (12) * ( 2,83) = 0,94 12-1 21,56