CAMBIOS DE BASE

De (10) a (2) 182(10)=101101110

De (2) a (10) 101101110(2)=182

De (16) a (10) B6(16)=182

De (10) a (16) 182(10)=B6

De (2) a (16) 101101110=B6

De (16) a (2) B6(16)=101101110

182(10)=182/2=91(R0) 91/2=45(R1) 45/2=22(R1) 22/2=11(R0) 11/2=5(R1) 5/2=2(R1) 2/2=1(R1) 101101110(2)=1*27+0*26+1*25+1*24+0*23+1*22+1*21+0*20=182 B6=11*161+6*160=182 182/16=11(R6) 11=B 1011=B 0110=6